Question
A number was divided successively in order by 4,5 and 6. The remainders were respectively 2,3 and 4. The number is
Answer: Option A
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`:.` z = 6 x 1 + 4 = 10.
y = 5 x z + 3 = 5 x 10 + 3 = 53.
`x` = 4 x y + 2 = 4 x 53 + 2 = 212 + 2 = 214.
Hence , required number = 214.
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