Question
50 is divided into two parts such that the sum of their reciprocals is 1/ 12.Find the two parts.
Answer: Option B
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Let the two parts be x and (50−x).
Then, 1 / x + 1 / (50−x) = 1 / 12 => (50−x + x) / x ( 50−x) = 1 / 12
↔x2−50x + 600 = 0 => (x−30) ( x−20) = 0 => x = 30 or x = 20.
So, the parts are 30 and 20.
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