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Question

1 + 2 + 3 + ... + 12 = ?
Options:
A .  66
B .  68
C .  76
D .  78
Answer: Option D

Answer : Option D

Explanation :

$MF#%1 + 2 + 3 + \cdots + n = \sum{n} = \dfrac{n(n+1)}{2}%$MF#%


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