Question
1 + 2 + 3 + ... + 12 = ?
1 + 2 + 3 + ... + 12 = ?
Answer: Option D
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Answer : Option D
Explanation :
$MF#%1 + 2 + 3 + \cdots + n = \sum{n} = \dfrac{n(n+1)}{2}%$MF#%
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