Question
(`1^2` + `2^2` + `3^2` +...........+ `10^2` ) = ?
Answer: Option D
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We now that ( `1^2` + `2^2` + `3^2` +............+ `n^2`) = `1/6` n(n+1)(2n + 1).
putting n= 10, required sum = (`1/6` x 10 x 11 x 21) = 385
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