1 - 1 + 1 - 2 + 1 - 3 + ... up to n terms = ? n n n Options: A . &nbsp 1 n 2 B . &nbsp 1 ( n - 1) 2 C . &nbsp 1 n ( n - 1) 2 D . &nbspNone of these

Answer: Option B Given sum = (1 + 1 + 1 + ... to n terms) - 1 + 2 + 3 + ... to n terms n n n = n - n 1 + 1 [ Ref : n th terms = ( n / n ) = 1] 2 n = n - n + 1 2 = 1 ( n - 1) 2

1 -1 +1 -2 +1 -3 + ... up to n terms = ?

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