Question
12 + 22 + 32 + ... + 82 = ?
Answer: Option A
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1
2
+
2
2
+
3
2
+
⋯
+
8
2
=
n
(
n
+
1
)
(
2
n
+
1
)
6
=
8
(
8
+
1
)
[
(
2
×
8
)
+
1
]
6
=
8
×
9
×
17
6
=
4
×
9
×
17
3
=
4
×
3
×
17
=
204
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