Question


(12 + 22 + 32 + ... + 102) = ?

Options:
A .  330
B .  345
C .  365
D .  385
Answer: Option D


We know that (12 + 22 + 32 + ... + n2) =
1
n(n + 1)(2n + 1)
6



Putting n = 10, required sum =
(12 + 22 + 32 + ... + 102) = ?
1
x 10 x 11 x 21
(12 + 22 + 32 + ... + 102) = ?
= 385
6


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