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Question

(12 + 22 + 32 + ... + 102) = ?


Options:
A .  330
B .  345
C .  365
D .  385
Answer: Option D

We know that (12 + 22 + 32 + ... + n2) = 1 n(n + 1)(2n + 1) 6

Putting n = 10, required sum =  (12 + 22 + 32 + ... + 102) = ?  1 x 10 x 11 x 21  (12 + 22 + 32 + ... + 102) = ?  = 385 6



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