Question
(12 + 22 + 32 + ... + 102) = ?
(12 + 22 + 32 + ... + 102) = ?
Answer: Option D
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Answer : Option D
Explanation :
$MF#%1^2 + 2^2 + 3^2 + \cdots + n^2 = \sum{n^2} = \dfrac{n(n+1)(2n + 1)}{6}$MF#%
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