Question
123 × 123 + 288 × 288 + 2 × 123 × 288 = ?
Answer: Option C
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Given Equation is in the form $$a^2+b^2+2ab$$ where a = 123 and b = 288
$$a^2+b^2+2ab=(a+b)^2$$
Hence answer = $$(a+b)^2=(123+288)^2=411^2=168921$$
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