Question

(112 + 122 + 132 + ... + 202) = ?

Options:
A .  385
B .  2485
C .  2870
D .  3255
Answer: Option B

(112 + 122 + 132 + ... + 202) = (12 + 22 + 32 + ... + 202) - (12 + 22 + 32 + ... + 102)



(112 + 122 + 132 + ... + 202) = ?
Ref: (12 + 22 + 32 + ... + n2) =
1
n(n + 1)(2n + 1)
(112 + 122 + 132 + ... + 202) = ?
   
6



(112 + 122 + 132 + ... + 202) = ?
20 x 21 x 41
-
10 x 11 x 21
(112 + 122 + 132 + ... + 202) = ?
6
6

= (2870 - 385)


= 2485.


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