(a) If AB || DE, ∠AOD = 50° and ∠DPC = 160°, find the value of ∠DBE?
(b) A 15 m long ladder reached a window 12 m high from the ground when placed against a wall at a distance 'a'. Find the distance of the foot of the ladder from the wall.
[4 MARKS]
:
(a) Steps: 1 Mark
Correct answer: 1 Mark
(b) Formula: 1 Mark
Result: 1 Mark
(a)
∠OAD=50°( given)∠DOC = 180°−50°=130°( linear pair )∠DPC = 160° (given)∠ DPO =180° − 160 °( Linear pair)∠DPO= 20°In △ DOP∠ODP =180°−(130° + 20 °) ( by angle sum property )∠ODP =30°In △ DBE∠DBE =180°−( 90° + 30° ) (By angle sum property )∠DBE = 60°
(b)
The wall and the ground are at right angle. Therefore the ladder, ground and the wall make the sides of a right-angled triangle.
∴a2+122=152
⇒a2=225−144=81
a=√81=9 m
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