100 ---- 100 --- 10
100 --- 10
--------------------
300 ---- 20 years
(4000*3*R)/100 = (5000*5*4)/100
R
= 8 1/3
4/9 P = (P*R*R)/100
R = 20/3 = 6 2/3%
(x*5*1)/100 + [(1500 - x)*6*1]/100 = 85
5x/100 + 90 “ 6x/100 = 85
x/100 = 5
=> x = 500
Simple interest = (18000 * 4 * 15)/100 = Rs. 10800Amount = P + I = 18000 + 10800 = Rs. 28800
I = (8200 * 2.5 * 17.5)/100 = (8200 * 5 * 35)/(100 * 2 * 2) = Rs. 3587.50
Let the interest for one year be x.As amount = Principal + Interest, we have P + 4x = 20720 --- (1) ; P + 6x = 24080 --- (2)Solving the equations (1) and (2), we can get P = Rs. 14000 and x = Rs. 1680Interest for one year on Rs. 14000 is Rs. 1680So, R = (100 * 1680)/(14000 * 1) = 12% p.a.
Let the pricipal be Rs. x, then amount = 3x(where R = rate of interest) => Interest = 3x - x = Rs. 2xR = (100 * 2x)/(x * 12) = 50/3 % = 16 2/3 %
T = (100 * 16500)/(15 * 5000) = 22 years