Quantitative Aptitude
VOLUME AND SURFACE AREA MCQs
Total Questions : 820
| Page 9 of 82 pages
Answer: Option C. -> 56 sq mt
 - area of rhombus = base × height = 7 cm × 8 cm = 56 sq cm
 - area of rhombus = base × height = 7 cm × 8 cm = 56 sq cm
Answer: Option D. -> 80 cm
 - Let the edge of the cubical box be “a” m.
Rs. 500 is the cost of 1 m3 wood
Rs. 256. is the cost of 1x256/500 m3 wood=0.512m3
So, Volume of total wood = 0.512m3
a x a x a = 0.512m3
a x a x a = 0.8 x 0.8 x0.8x
The length of each side = 0.8m=80cm
 - Let the edge of the cubical box be “a” m.
Rs. 500 is the cost of 1 m3 wood
Rs. 256. is the cost of 1x256/500 m3 wood=0.512m3
So, Volume of total wood = 0.512m3
a x a x a = 0.512m3
a x a x a = 0.8 x 0.8 x0.8x
The length of each side = 0.8m=80cm
Answer: Option D. -> 270
 - The volume of the cylinder = Area of base x height =45 sq.cm x 6 cm
=270cm3
 - The volume of the cylinder = Area of base x height =45 sq.cm x 6 cm
=270cm3
Answer: Option C. -> 45 sq mt
 - Given: L : H = 5 : 2 Þ H : B = 4 : 5
L : H : B = 20 : 8 : 10
Area of four walls of a room is =2(l + b) h = 108 Þ (l + b) h = 54
(20 x + 10x) x 8x = 54
240x2 = 54
x2 = 54 / 240
x2 = 0.225
The area of floor of the room = l x b =l × b = 20x × 10x =200x2 =200x 225= 45m2
 - Given: L : H = 5 : 2 Þ H : B = 4 : 5
L : H : B = 20 : 8 : 10
Area of four walls of a room is =2(l + b) h = 108 Þ (l + b) h = 54
(20 x + 10x) x 8x = 54
240x2 = 54
x2 = 54 / 240
x2 = 0.225
The area of floor of the room = l x b =l × b = 20x × 10x =200x2 =200x 225= 45m2
Answer: Option D. -> 5 sq cm
 - Area of square = 2cm2
Side of square = square root of 2
Let r be the radius of the circle and adjust it like that it forms a right angle triangle then
r2 = (square root of 2)2 + (square root of 2 / 2)2
r2 = 2 + ( 2 / 4)
r2 = 5 / 2
r = square root of ( 5 / 2)
In a full square the diagonal of square will be the diameter of the cirlcle.
r = square root of ( 5 / 2) is this so diameter = 2 x square root of (5 / 2)
Diagonal of square = side x square root of 2
side x square root of 2 = 2 x square root of 5 / square root of 2
side x 2 = 2 x square root of 5
side = square root of 5
Area of square = r2
= (square root of 5)2
= 5 cm2
 - Area of square = 2cm2
Side of square = square root of 2
Let r be the radius of the circle and adjust it like that it forms a right angle triangle then
r2 = (square root of 2)2 + (square root of 2 / 2)2
r2 = 2 + ( 2 / 4)
r2 = 5 / 2
r = square root of ( 5 / 2)
In a full square the diagonal of square will be the diameter of the cirlcle.
r = square root of ( 5 / 2) is this so diameter = 2 x square root of (5 / 2)
Diagonal of square = side x square root of 2
side x square root of 2 = 2 x square root of 5 / square root of 2
side x 2 = 2 x square root of 5
side = square root of 5
Area of square = r2
= (square root of 5)2
= 5 cm2
Answer: Option B. -> 306.2
 - Internal diameter = 11.2 cm
Internal radius= 11.2/2 = 5.6 cm Length of the tube = 21 cm
Volume of the internal cylinder π r 2 h = 22x 5.6x5.6x21/7 =2069.76cm 2
External radius, R = (5.6 + 0.4) cm = 6 cm
Volume of the external cylinder = πR2 h =22x6x6x21/7=2376cm2
Now, volume of the metal = Volume of the external diameter – Volume of the internal diameter
= (2376 – 2069.76) cm3 = 306.24 cm3 = 306.2 cm3
 - Internal diameter = 11.2 cm
Internal radius= 11.2/2 = 5.6 cm Length of the tube = 21 cm
Volume of the internal cylinder π r 2 h = 22x 5.6x5.6x21/7 =2069.76cm 2
External radius, R = (5.6 + 0.4) cm = 6 cm
Volume of the external cylinder = πR2 h =22x6x6x21/7=2376cm2
Now, volume of the metal = Volume of the external diameter – Volume of the internal diameter
= (2376 – 2069.76) cm3 = 306.24 cm3 = 306.2 cm3
Answer: Option C. -> Rs 120.64
 - Area of the tin sheet required = Area of 20 oil tins
= 20 × 2 (lb + bh + hl) = 20x2(26x26+26x45+45x26)=12.06m2
Cost of 1 m2 tin sheet = Rs.10
Cost of 12.064 m2 tin sheet = Rs.10 2.064 = Rs.120.64
So, total cost for making 20 such tins = Rs.120.64
 - Area of the tin sheet required = Area of 20 oil tins
= 20 × 2 (lb + bh + hl) = 20x2(26x26+26x45+45x26)=12.06m2
Cost of 1 m2 tin sheet = Rs.10
Cost of 12.064 m2 tin sheet = Rs.10 2.064 = Rs.120.64
So, total cost for making 20 such tins = Rs.120.64
Answer: Option B. -> 750 cu. m
 -
 -
1 hectare = 10,000 m2
So, Area = (1.5 x 10000) m2 = 15000 m2.
Volume = (Area x Depth) = 15000 x 1 m3 = 750 m3. 20
Answer: Option A. -> 84
 - Let the length of the wire be h.
Radius = 1 mm = 1 cm. Then, 2 20
22 x 1 x 1 x h = 66. 7 20 20
h = 66 x 20 x 20 x 7 = 8400 cm = 84 m. 22
 - Let the length of the wire be h.
Radius = 1 mm = 1 cm. Then, 2 20
22 x 1 x 1 x h = 66. 7 20 20
h = 66 x 20 x 20 x 7 = 8400 cm = 84 m. 22
Answer: Option B. -> 3.696 kg
 - External radius = 4 cm,
Internal radius = 3 cm.
Volume of iron = 22 x [(4)2 - (3)2] x 21 cm3 7
= 22 x 7 x 1 x 21 cm3 7
= 462 cm3.
Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg
 - External radius = 4 cm,
Internal radius = 3 cm.
Volume of iron = 22 x [(4)2 - (3)2] x 21 cm3 7
= 22 x 7 x 1 x 21 cm3 7
= 462 cm3.
Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg