Quantitative Aptitude
TIME AND WORK MCQs
Time & Work, Work And Wages
Total Questions : 1512
| Page 3 of 152 pages
Answer: Option A. -> 2 days
Answer: Option C. -> 18.75
Answer: Option B. -> 24 , 40 , 30
Answer: Option B. -> \(8\frac{1}{3}\) days
Answer: Option C. -> \(7\frac{1}{2}days\)
Answer: Option C. -> 15 days
Answer: Option A. -> \(22\frac{1}{2}\) days
Answer: Option B. -> 20 days
To solve this problem, we first need to calculate Ashok's efficiency in terms of work done per day. If Ashok worked for 6 days and only 1/3rd of the work has been done, then his efficiency can be calculated as follows:
Work done by Ashok in 6 days = 1/3 of the total workWork done by Ashok per day = 1/3 of the total work ÷ 6 days = 1/18 of the total work
Next, we need to calculate Ravi's efficiency in terms of work done per day. Ravi is 60% as efficient as Ashok, so his efficiency can be calculated as follows:
Work done by Ravi per day = 60% of Ashok's efficiency = 60% of 1/18 of the total work
Finally, we need to calculate the number of days Ravi would take to complete the remaining 2/3rd of the work. We can use the formula:
Time taken by Ravi to complete the work = Remaining work ÷ Ravi's efficiency per day
Substituting the values, we get:
Time taken by Ravi to complete the work = 2/3 of the total work ÷ (60% of 1/18 of the total work) = 20 days
Here is a summary of the key points in bullet form:
To solve this problem, we first need to calculate Ashok's efficiency in terms of work done per day. If Ashok worked for 6 days and only 1/3rd of the work has been done, then his efficiency can be calculated as follows:
Work done by Ashok in 6 days = 1/3 of the total workWork done by Ashok per day = 1/3 of the total work ÷ 6 days = 1/18 of the total work
Next, we need to calculate Ravi's efficiency in terms of work done per day. Ravi is 60% as efficient as Ashok, so his efficiency can be calculated as follows:
Work done by Ravi per day = 60% of Ashok's efficiency = 60% of 1/18 of the total work
Finally, we need to calculate the number of days Ravi would take to complete the remaining 2/3rd of the work. We can use the formula:
Time taken by Ravi to complete the work = Remaining work ÷ Ravi's efficiency per day
Substituting the values, we get:
Time taken by Ravi to complete the work = 2/3 of the total work ÷ (60% of 1/18 of the total work) = 20 days
Here is a summary of the key points in bullet form:
- Ashok worked for 6 days and only 1/3rd of the work has been done, so his efficiency per day can be calculated as 1/18 of the total work.
- Ravi is 60% as efficient as Ashok, so his efficiency per day can be calculated as 60% of 1/18 of the total work.
- The time taken by Ravi to complete the remaining 2/3rd of the work can be calculated using the formula: Remaining work ÷ Ravi's efficiency per day = 20 days.
Answer: Option A. -> 3 days
Answer: Option B. -> 180 sq. m
Let the total area of the tank be 'A' square metres, and the area of the plastered portion of the tank be 'x' square metres. Therefore, the remaining area to be plastered is (A - x) square metres.
Given that the workers completed 1/2 of the work in one day, therefore the plastered area on the first day is (1/2)*A.
The remaining area to be plastered after the first day is (A - (1/2)*A) = (1/2)*A.
Given that the workers completed 1/3rd of the remaining work on the next day, therefore the area plastered on the second day is (1/3)*((1/2)*A) = (1/6)*A.
The total area plastered is the sum of the areas plastered on both days, i.e.,
x = (1/2)*A + (1/6)*A = (2/3)*A.
The area remaining to be plastered is given as 60 square metres, i.e.,
A - x = 60.
Substituting the value of x from above, we get:
A - (2/3)*A = 60,
which gives us (1/3)*A = 60.
Therefore, the total area of the tank is:
A = 180 square metres.
Hence, the area of the tank that is to be plastered is:
(A - x) = A - (2/3)*A = (1/3)A = 60(3) = 180 square metres.
Therefore, option B, i.e., 180 sq. m is the correct answer.If you think the solution is wrong then please provide your own solution below in the comments section .
Let the total area of the tank be 'A' square metres, and the area of the plastered portion of the tank be 'x' square metres. Therefore, the remaining area to be plastered is (A - x) square metres.
Given that the workers completed 1/2 of the work in one day, therefore the plastered area on the first day is (1/2)*A.
The remaining area to be plastered after the first day is (A - (1/2)*A) = (1/2)*A.
Given that the workers completed 1/3rd of the remaining work on the next day, therefore the area plastered on the second day is (1/3)*((1/2)*A) = (1/6)*A.
The total area plastered is the sum of the areas plastered on both days, i.e.,
x = (1/2)*A + (1/6)*A = (2/3)*A.
The area remaining to be plastered is given as 60 square metres, i.e.,
A - x = 60.
Substituting the value of x from above, we get:
A - (2/3)*A = 60,
which gives us (1/3)*A = 60.
Therefore, the total area of the tank is:
A = 180 square metres.
Hence, the area of the tank that is to be plastered is:
(A - x) = A - (2/3)*A = (1/3)A = 60(3) = 180 square metres.
Therefore, option B, i.e., 180 sq. m is the correct answer.If you think the solution is wrong then please provide your own solution below in the comments section .
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