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Quantitative Aptitude

SURDS AND INDICES MCQs

Surds & Indices, Indices And Surds, Power

Total Questions : 753 | Page 3 of 76 pages
Question 21.

  1. If\(\frac{9^{n}(3^{2})(3^{\frac{- n}{2}})^{- 2}-27^{n}}{3^{3m}(2^{3})} = \frac{1}{27} \), then

  1.    m + n +1
  2.    m – n = 1
  3.    n + m= – 1 
  4.    n – m = 1
 Discuss Question
Answer: Option B. -> m – n = 1
Question 22.

  \(\frac{\sqrt{a^{5}}\times\sqrt[3]{b^{2}}}{\sqrt[6]{b^{- 2}}\times\sqrt[4]{a^{10}}}\)  = ? 

  1.    a
  2.    b
  3.    ab
  4.    none of these
 Discuss Question
Answer: Option B. -> b
Question 23.

  1. If 2x = 8y+1 and 9y = 3x-9, then y equals

  1.    3
  2.    6
  3.    9
  4.    12
 Discuss Question
Answer: Option C. -> 9
Question 24.

  1. If 4x =\(\sqrt{2^{3y}}\), then

  1.    \(x=\frac{3}{4}y\)
  2.    \(y=\frac{3}{4}x\)
  3.    \(x=\frac{1}{3}y\)
  4.    \(y=\frac{1}{3}x\)
 Discuss Question
Answer: Option A. -> \(x=\frac{3}{4}y\)
Question 25.

  1. \(\frac{\sqrt{5}+ x}{\sqrt{5}- x}\)  = 1 then x =?

  1.    0
  2.    1
  3.    - 1
  4.    none of these
 Discuss Question
Answer: Option C. -> - 1
Question 26.

 \([(\sqrt{6}+ \sqrt{3})(\sqrt{6}- \sqrt{3})]^{\frac{3}{2}}\)  is nearly equal to

  1.    \(2\sqrt{3}\)
  2.    \(3\sqrt{3}\)
  3.    \(2\sqrt{18}\)
  4.    none of these
 Discuss Question
Answer: Option B. -> \(3\sqrt{3}\)
Question 27.

  1. If \(\frac{a}{b}=\frac{c}{d}=\frac{3}{5}\)  , then  \([\frac{a^{4}+c^{4}}{b^{4}+d^{4}}]^{\frac{1}{4}}\)  =?

  1.    \(\frac{5}{3}\)
  2.    \(\frac{3}{5}\)
  3.    \(\frac{7}{3}\)
  4.    \(\frac{3}{7}\)
 Discuss Question
Answer: Option B. -> \(\frac{3}{5}\)
Question 28.

  1. If n < (1+\(\sqrt{2}\))² < n + 1, find the value f n assuming that n is an integer.

  1.    3
  2.    4
  3.    5
  4.    6
 Discuss Question
Answer: Option C. -> 5
Question 29.

  1. If a =\(\frac{1}{2 - \sqrt{3}}\), b =\(\frac{1}{2 +\sqrt{3}}\)find the value of 7a² + 11ab – 7b².

  1.    \(13 + 11\sqrt{56}\)
  2.    \(11 + 13\sqrt{56}\)
  3.    \(11 + 56\sqrt{3}\)
  4.    none of these
 Discuss Question
Answer: Option C. -> \(11 + 56\sqrt{3}\)
Question 30.

(17)3.5 x (17)? = 178

  1.    2.29
  2.    2.75
  3.    4.25
  4.    4.5
 Discuss Question
Answer: Option D. -> 4.5

Let (17)3.5 x (17)x = 178.


Then, (17)3.5 + x = 178.


So, 3.5 + x = 8


 x = (8 - 3.5)


 x = 4.5

Given:

(17)^3.5 x (17)^? = 17^8

To find: the value of the exponent '?'

Solution:

We can simplify the left-hand side of the equation using the laws of exponents:

(17)^3.5 x (17)^? = 17^8

(17)^(3.5 + ?) = 17^8

Since the bases are the same, we can equate the exponents:

3.5 + ? = 8

? = 8 - 3.5

? = 4.5

Therefore, the answer is option D (4.5).

Explanation:

  • Exponents or powers are a way of representing repeated multiplication. For example, a^3 means "a multiplied by itself three times."
  • The product of two exponential expressions with the same base can be simplified by adding their exponents. For example, a^3 x a^4 = a^(3+4) = a^7.
  • In this problem, we are given the product of two exponential expressions with the same base, (17)^3.5 and (17)^?. We can simplify this product by adding the exponents: (17)^(3.5 + ?).
  • We are also given that this product is equal to (17)^8, which allows us to equate the exponents and solve for the unknown exponent '?'.
  • The final result is that '?' is equal to 4.5, which means that (17)^4.5 is the second term in the original product.

Formula:

  • a^m x a^n = a^(m+n)

Key takeaways:

  • When working with exponents, it is important to keep track of the base and the exponent separately, and to apply the laws of exponents to simplify expressions.
  • Equating the exponents of exponential expressions with the same base can be a powerful technique for solving problems involving exponents.

If you think the solution is wrong then please provide your own solution below in the comments section .

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