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Quantitative Aptitude

SQUARE ROOT AND CUBE ROOT MCQs

Square Roots, Cube Roots, Squares And Square Roots

Total Questions : 547 | Page 42 of 55 pages
Question 411.

The square root of (7 + 35) (7 - 35) is


  1.    5
  2.    2
  3.    4
  4.    35
 Discuss Question
Answer: Option B. -> 2

(7 + 35)(7 - 35) = (7)2 - (35)2  = 49 - 45  = 4  = 2.


Question 412.
$MF#%\sqrt{0.000256 \times \text{?}} = 1.6. $MF#%
  1.    0.1
  2.    10
  3.    10000
  4.    1000
 Discuss Question
Answer: Option C. -> 10000

Answer : Option C

Explanation :

$MF#%\sqrt{0.000256 \times x} = 1.6 \\\\ \Rightarrow 0.000256 \times x = (1.6)^2 \\\\ \Rightarrow 0.000256\times x = 2.56 \\\\ \Rightarrow x = \dfrac{2.56}{0.000256} = \dfrac{2560000}{256} = 10000$MF#%


Question 413.
What is the square root of 0.0009?



  1.    0.13
  2.    0.03
  3.    1.13
  4.    0.02
 Discuss Question
Answer: Option B. -> 0.03

√0.0009
= √(9 / 10000)
= 3 / 100
= 0.03.



Question 414.
If √(1 + (x / 144)) = 13 / 12, the find the value of x.



  1.    25
  2.    20
  3.    29
  4.    27
 Discuss Question
Answer: Option A. -> 25


√(1 + (x / 144)) = 13 / 12
( 1 + (x / 144)) = (13 / 12 )2
= 169 / 144
x / 144 = (169 / 144) - 1
x / 144 = 25/144
x = 25.


Question 415.
$MF#%\text{if }x = \dfrac{\sqrt{3}+1}{\sqrt{3}-1}\text{ and }y = \dfrac{\sqrt{3}-1}{\sqrt{3}+1}\text{, what is the value of }(x^2+y^2)$MF#%
  1.    15
  2.    14
  3.    13
  4.    10
 Discuss Question
Answer: Option B. -> 14

Answer : Option B

Explanation :

$MF#%\begin{align}&x = \dfrac{\left(\sqrt{3}+1\right)}{\left(\sqrt{3}-1\right)} = \dfrac{\left(\sqrt{3}+1\right)\left(\sqrt{3}+1\right)}{\left(\sqrt{3}-1\right)\left(\sqrt{3}+1\right)} = \dfrac{\left(\sqrt{3}+1\right)^2}{3-1} = \dfrac{3 + 2\sqrt{3} + 1}{2}= \dfrac{4 + 2\sqrt{3}}{2} = 2 + \sqrt{3}\\\\
&y = \dfrac{\sqrt{3}-1}{\sqrt{3}+1}= \dfrac{\left(\sqrt{3}-1\right)\left(\sqrt{3}-1\right)}{\left(\sqrt{3}+1\right)\left(\sqrt{3}-1\right)} = \dfrac{\left(\sqrt{3}-1\right)^2}{3-1} = \dfrac{3 - 2\sqrt{3} + 1}{2}= \dfrac{4 - 2\sqrt{3}}{2} = 2 - \sqrt{3}\\\\
&x^2 + y^2 = \left(2 + \sqrt{3}\right)^2 + \left(2 - \sqrt{3}\right)^2 = (4 + 4\sqrt{3}+3) + (4 - 4\sqrt{3}+3) = 2(4+3)= 14\end{align}$MF#%


Question 416.


The cube root of .000216 is:

  1.    .6
  2.    .06
  3.    77
  4.    87
 Discuss Question
Answer: Option B. -> .06


(.000216)1/3
=
The Cube Root Of .000216 Is:
216
The Cube Root Of .000216 Is:
1/3
106



   =
The Cube Root Of .000216 Is:
6 x 6 x 6
The Cube Root Of .000216 Is:
1/3
102 x 102 x 102



   =
6
102



   =
6
100


   = 0.06


Question 417.

1.5625 = ?

  1.    1.05
  2.    1.25
  3.    1.45
  4.    1.55
 Discuss Question
Answer: Option B. -> 1.25
1|1.5625( 1.25
|1
|-------
22| 56
| 44
|-------
245| 1225
| 1225
|-------
| X
|-------

1.5625 = ? 1.5625 = 1.25.


Question 418.


If 35 + 125 = 17.88, then what will be the value of 80 + 65 ?

  1.    13.41
  2.    20.46
  3.    21.66
  4.    22.35
 Discuss Question
Answer: Option D. -> 22.35

35 + 125 = 17.88


If 35 + 125 = 17.88, Then What Will Be The Value Of 80 + 65 ... 35 + 25 x 5 = 17.88


If 35 + 125 = 17.88, Then What Will Be The Value Of 80 + 65 ... 35 + 55 = 17.88


If 35 + 125 = 17.88, Then What Will Be The Value Of 80 + 65 ... 85 = 17.88


If 35 + 125 = 17.88, Then What Will Be The Value Of 80 + 65 ... 5 = 2.235


If 35 + 125 = 17.88, Then What Will Be The Value Of 80 + 65 ... 80 + 65 = 16 x 5 + 65


   = 45 + 65


   = 105 = (10 x 2.235) = 22.35


Question 419.


What should come in place of both x in the equation
x
=
162
.
128
x

  1.    12
  2.    14
  3.    144
  4.    196
 Discuss Question
Answer: Option A. -> 12


Let
x
=
162
128
x


Then x2 = 128 x 162


   = 64 x 2 x 18 x 9


   = 82 x 62 x 32


   = 8 x 6 x 3


   = 144.


What Should Come In Place Of Both X In The Equationx=162.128... x = 144 = 12.


Question 420.


The least perfect square, which is divisible by each of 21, 36 and 66 is:

  1.    213444
  2.    214344
  3.    214434
  4.    231444
 Discuss Question
Answer: Option A. -> 213444

L.C.M. of 21, 36, 66 = 2772.


Now, 2772 = 2 x 2 x 3 x 3 x 7 x 11


To make it a perfect square, it must be multiplied by 7 x 11.


So, required number = 22 x 32 x 72 x 112 = 213444


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