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Quantitative Aptitude

SQUARE ROOT AND CUBE ROOT MCQs

Square Roots, Cube Roots, Squares And Square Roots


Total Questions : 547 | Page 41 of 55 pages
Question 401.
√2 = 1.4142, find the value of √2 / (2 + √2).



  1.    0.4143
  2.    0.4042
  3.    0.4142
  4.    0.3142
 Discuss Question
Answer: Option C. -> 0.4142



Question 402.

If 5 = 2.236, then the value of 5 - 10 + 125 is equal to: 2 5


  1.    5.59
  2.    7.826
  3.    8.944
  4.    10.062
 Discuss Question
Answer: Option B. -> 7.826

5 - 10 + 125 = (5)2 - 20 + 25 x 55 2 5 25

= 5 - 20 + 50 25

= 35 x 5 25 5

= 355 10

= 7 x 2.236 2

= 7 x 1.118

= 7.826


Question 403.
$MF#%\sqrt{0.0576 \times \text{?}} = 0.24. $MF#%
  1.    None of these
  2.    10
  3.    1
  4.    0.1
 Discuss Question
Answer: Option C. -> 1

Answer : Option C

Explanation :

$MF#%\sqrt{0.0576 \times x} = 0.24. \\\\ \Rightarrow
0.0576 \times x = (0.24)^2 \\\\ \Rightarrow 0.0576 \times x = 0.0576 \\\\ \Rightarrow x = 1$MF#%


Question 404.
If a * b * c = (√(a + 2)(b + 3)) / (c + 1), find the value of 6 * 15 * 3.



  1.    3
  2.    4
  3.    8
  4.    9
 Discuss Question
Answer: Option A. -> 3

6 * 15 * 3 = (√(6 + 2)(15 + 3)) / (3 + 1)
= (√8 * 18) / 4 = √144 / 4
= 12 / 4 = 3.



Question 405.

The cube root of .000216 is:


  1.    .6
  2.    .06
  3.    77
  4.    87
 Discuss Question
Answer: Option B. -> .06

(.000216)1/3 =  The Cube Root Of .000216 Is:  216  The Cube Root Of .000216 Is:  1/3 106

   =  The Cube Root Of .000216 Is:  6 x 6 x 6  The Cube Root Of .000216 Is:  1/3 102 x 102 x 102

   = 6 102

   = 6 100

   = 0.06


Question 406.
A man plants 49284 apple trees in his garden and arranges them so that there are as many rows as there are apples trees in each row. The number of rows is
  1.    182
  2.    202
  3.    222
  4.    122
 Discuss Question
Answer: Option C. -> 222

Answer : Option C

Explanation :

Let n be the number of rows
Then n × n = 49284

$MF#%\text{ie, n = }\sqrt{49284} = 222$MF#%


Question 407.
$MF#%\sqrt{41-\sqrt{21+\sqrt{19 - \sqrt{9}}}} = \text{?}$MF#%
  1.    3
  2.    4
  3.    5
  4.    6
 Discuss Question
Answer: Option D. -> 6

Answer : Option D

Explanation :

$MF#%\sqrt{41-\sqrt{21+\sqrt{19 - \sqrt{9}}}} = \sqrt{41-\sqrt{21+\sqrt{19 - 3}}} = \sqrt{41-\sqrt{21+\sqrt{16}}}\\\\\ =\sqrt{41-\sqrt{21+4}} =\sqrt{41-\sqrt{25}}=\sqrt{41-5} =\sqrt{36} = 6$MF#%


Question 408.

The square root of 64009 is:


  1.    253
  2.    347
  3.    363
  4.    803
 Discuss Question
Answer: Option A. -> 253

2|64009( 253 |4 |---------- 45|240 |225 |---------- 503| 1509 | 1509 |---------- | X |----------

 The Square Root Of 64009 Is:  64009 = 253.


Question 409.
A group of students decided to collect as many paise from each member of group as is the number of members. If the total collection amounts to Rs. 98.01, the number of the member is the group is:
  1.    101
  2.    98
  3.    99
  4.    88
 Discuss Question
Answer: Option C. -> 99

Answer : Option C

Explanation :

Let the number of members = n
Then n2 = Total amount of money collected = 9801 paise

$MF#%\text{ie, }n=\sqrt{9801} = 99$MF#%
i.e., number of members = 99


Question 410.
If √3 = 1.732, find the value of √192 - 1/2*√48 - √75 correct to 3 places 2 of decimal.



  1.    0.731
  2.    1.732
  3.    1.721
  4.    1.722
 Discuss Question
Answer: Option B. -> 1.732

√192 - (1 / 2)√48 - √75
= √64 * 3 - (1/2) √16 * 3 - √ 25 * 3
=8√3 - (1/2) * 4√3 - 5√3
=3√3 - 2√3
= √3
= 1.732


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