Answer : Option A

Explanation :

$MF#%\sqrt[3]{\sqrt{0.000064}} = \sqrt[3]{\sqrt{\dfrac{64}{10^6}}} = \sqrt[3]{\dfrac{\sqrt{64}}{\sqrt{10^6}}} = \sqrt[3]{\dfrac{8}{10^3}}=\sqrt[3]{\dfrac{8}{1000}} = \dfrac{\sqrt[3]{8}}{\sqrt[3]{10}} = \dfrac{2}{10} = 0.2$MF#%

√ 0.09 
=√ 9 / 100 
=3 / 10
=0.3, which is rational.

Answer : Option D

Explanation :

3600 = 2⁴ × 3² × 5²
ie, the smallest number by which 3600 be divided to make it a perfect cube
= 2 × 3² × 5² = 2 × 9 × 25 = 450

A number ending in 8 can never be a perfect square.

Let x = 162 128 x

Then x² = 128 x 162

   = 64 x 2 x 18 x 9

   = 8² x 6² x 3²

   = 8 x 6 x 3

   = 144.

x = 144 = 12.

Answer : Option D

Explanation :

$MF#%\sqrt{(14 + 2\sqrt{13})(14 - 2\sqrt{13})} = \sqrt{(14)^2 - (2\sqrt{13})^2} = \sqrt{196 - (4 \times 13)}\\\\ = \sqrt{196 - 52} = \sqrt{144} = 12$MF#%

Money collected=(59.29 x 100 )paise
=5929 paise.
Number of members√ 59291 
=77.

√(5/3) =√(5 * 3) / (3 * 3)
=√15 / 3
= 3.88 / 3
= 1.2933..
= 1.293.

√(0.289 / 0.00121)
= √(0.28900/0.00121)
= √(28900/121)
= 170 / 11.

Answer : Option A

Explanation :

$MF#%\sqrt{\dfrac{0.289}{0.00121}}+ \sqrt{9} = \sqrt{\dfrac{28900}{121}} + 3 = \dfrac{\sqrt{28900}}{\sqrt{121}}+3 =\dfrac{170}{11} + 3 = 15.45+3 = 18.45$MF#%