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Quantitative Aptitude

SQUARE ROOT AND CUBE ROOT MCQs

Square Roots, Cube Roots, Squares And Square Roots


Total Questions : 547 | Page 30 of 55 pages
Question 291.

If 3a = 4b = 6c and a + b + c = `27sqrt(29)`, then `sqrt(a^2 + b^2 + c^2 )` is :


  1.    `3sqrt(29)`
  2.    81
  3.    87
  4.    None of these
 Discuss Question
Answer: Option C. -> 87

`:.`  `sqrt(a^2 + b^2 + c^2)` =  `sqrt((a + b + c)^2 - 2(ab + bc + ca))`

= `sqrt((27sqrt(29))^2 - 2(2c xx 3/2 c + 4/2 c xx c  + c xx 2c))`

=`sqrt((729xx 29) - 2(3c^2 + 3/2 c^2 + 2c^2))`

= `sqrt((729 xx 29) - 2 xx 13/2 c^2)`

=`sqrt((729 xx 29) - 13 xx (6sqrt(29))^2)`

= `sqrt(29(729  - 468))`

=`sqrt(29 xx 261)` = `sqrt(29 xx 29 xx 9)` =   29 x 3 =  87.



Question 292.

The square root of `((0.75)^3)/(1 - 0.75)` + [0.75 +` (0.75)^2` + 1]  is :


  1.    1
  2.    2
  3.    3
  4.    4
 Discuss Question
Answer: Option B. -> 2

`((0.75)^3)/(1 - 0.75)` + [0.75 +` (0.75)^2` + 1]

=`sqrt(((0.75)^3 + (1 - 0.75) [(1)^2 + (0.75)^2 + 1 xx 0.75])/(1 - 0.75))`

=`sqrt(((0.75)^3 + [(1)^3 - (0.75)^3])/( 1 - 0.75))` =  `sqrt(1/0.25)` =  `sqrt(100/25)` =  `sqrt(4)` = 2



Question 293.

If a = 0.1039, then the value of `sqrt(4a^2 - 4a + 1) + 3a` is


  1.    0.1039
  2.    0.2078
  3.    1.1039
  4.    2.1039
 Discuss Question
Answer: Option C. -> 1.1039

`sqrt(4a^2 - 4a + 1) + 3a` = `sqrt((1)^2 + (2a)^2 - 2 xx 1 xx 2a)` + 3a

`sqrt((1 + 2a)^2) + 3a` =  (1 - 2a) + 3a =  (1 + a) = (1 + 0.1039) =  1.1039.



Question 294.

`(sqrt(2) + 1/sqrt(2))^2` is equal to :


  1.    `2 1/2`
  2.    `3 1/2`
  3.    `4 1/2`
  4.    `5 1/2`
 Discuss Question
Answer: Option C. -> `4 1/2`

`(sqrt(2) + 1/sqrt(2))^2` = `(sqrt(2))^2 + (1/sqrt(2))^2 + 2 xx sqrt(2) xx 1/sqrt(2)` =  2 + `1/2` + 2 = 4+ `1/2` = `4 1/2`



Question 295.

`(sqrt(3) - 1/sqrt(3))^2`  simplifies to :


  1.    `3/4`
  2.    `4/sqrt(3)`
  3.    `4/3`
  4.    None of these
 Discuss Question
Answer: Option C. -> `4/3`

`(sqrt(3) - 1/sqrt(3))^2`= `(sqrt(3))^2+ (1/sqrt(3))^2 - 2xxsqrt(3)xx 1/sqrt(3)`

= 3 +` 1/3`- 2 = 1 + `1/3` = `4/3`



Question 296.

The square root of `( 7 + 3sqrt(5)) (7 - 3sqrt(5))`  is


  1.    `sqrt(5)`
  2.    2
  3.    4
  4.    `3sqrt(5)`
 Discuss Question
Answer: Option B. -> 2

`sqrt((7 + 3sqrt(5)) (7 - 3sqrt(5)))` = `sqrt((7)^2 - (3sqrt(5))^2)` =  ` sqrt(49 - 45)` = `sqrt(4)` = 2.



Question 297.

The value of `sqrt(((0.03)^2 + (0.21)^2  + (0.065)^2)/((0.003)^2 + (0.021)^2+ (0.0065)^2))`   is


  1.    0.1
  2.    10
  3.    `10^2`
  4.    `10^3`
 Discuss Question
Answer: Option B. -> 10

Given exp. = `sqrt(((0.03)^2 + (0.21)^2  + (0.065)^2)/((0.003)^2 + (0.021)^2+ (0.0065)^2))`

=`sqrt(((0.03)^2 + (0.21)^2  + (0.065)^2)/((0.03/10)^2 + (0.21/10)^2+ (0.065/10)^2))`

=`sqrt((100[(0.03)^2 + (0.21)^2 + (0.065)^2])/((0.03)^2 + (0.21)^2 + (0.065)^2))` = `sqrt(100) `= 10



Question 298.

`sqrt((9.5 xx 0.85)/(.0017 xx .19))` equals :


  1.    .05
  2.    5
  3.    50
  4.    500
 Discuss Question
Answer: Option C. -> 50

Given exp. = `sqrt((9.5 xx 0.85)/(.0017 xx .19))` = `sqrt((9.5 xx .08500)/(.19 xx .0017))`

= `sqrt((95 xx 8500)/(19 xx 17))` =  `sqrt(5 xx 500)` =  `sqrt(2500)` =  50.



Question 299.

`sqrt((0.081 xx 0.324 xx 4.624)/(1.5625 xx 0.0289 xx 72.9 xx 64))`  is equal to :


  1.    0.024
  2.    0.24
  3.    2.4
  4.    24
 Discuss Question
Answer: Option A. -> 0.024

Given exp. = `sqrt((81 xx 324 xx 4624)/(15625 xx 289 xx 729 xx 64))`

                 = `(9 xx 18 xx 68)/(125 xx 17 xx 27 xx 8)`=  `3/125`=  0.024.



Question 300.

`sqrt((0.204 xx 42)/(0.07 xx 3.4))`  is  equal to :


  1.    `1/6`
  2.    0.06
  3.    0.6
  4.    6
 Discuss Question
Answer: Option D. -> 6

 Given exp.`sqrt((0.204 xx 42)/(0.07 xx 3.4))` =  `sqrt((204 xx 42)/(7 xx34))` = ` sqrt(36)` =  6.


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