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MCQs

Total Questions : 113 | Page 1 of 12 pages
Question 1. The standard penetration test is performed in clear hole of _____________ mm in diameter.
  1.    10 to 30
  2.    30 to 50
  3.    55 to 150
  4.    150 to 1000
 Discuss Question
Answer: Option C. -> 55 to 150
Answer: (c).55 to 150
Question 2. The sampler in standard penetration test has outer diameter of _________ mm.
  1.    50.8
  2.    60.3
  3.    70.3
  4.    80.2
 Discuss Question
Answer: Option A. -> 50.8
Answer: (a).50.8
Question 3. The sample in standard penetration test has inner diameter of _________ mm.
  1.    50.8
  2.    60
  3.    35
  4.    75
 Discuss Question
Answer: Option C. -> 35
Answer: (c).35
Question 4. The sample is driven by a weight of _____________ in sample in standard penetration test.
  1.    65 kg
  2.    14 kg
  3.    55 kg
  4.    100 kg
 Discuss Question
Answer: Option A. -> 65 kg
Answer: (a).65 kg
Question 5. The height of the free fall in sample in standard penetration test is ___________
  1.    50 cm
  2.    75 cm
  3.    100 cm
  4.    150 cm
 Discuss Question
Answer: Option B. -> 75 cm
Answer: (b).75 cm
Question 6. When deeper layers have increasingly greater density, the seismic refraction method is fast.
  1.    True
  2.    False
  3.    May be True or False
  4.    Can't say
 Discuss Question
Answer: Option A. -> True
Answer: (a).True
Question 7. If σ’ is the effective overburden pressure, then the effective penetration resistance is given by _____________
  1.    Nₑ=\(N \frac{50}{1.42σ^{‘}}\)
  2.    Nₑ=\(N \frac{50}{σ^{‘}+10}\)
  3.    Nₑ=\(N \frac{1}{1.42σ^{‘}+10}\)
  4.    Nₑ=\(N \frac{50}{1.42σ^{‘}+10}\)
 Discuss Question
Answer: Option D. -> Nₑ=\(N \frac{50}{1.42σ^{‘}+10}\)
Answer: (d).Nₑ=\(N \frac{50}{1.42σ^{‘}+10}\)
Question 8. The essential feature of reinforced earth is that __________ develops between compacted layer of earth and reinforcing elements.
  1.    friction
  2.    tension
  3.    compression
  4.    shear
 Discuss Question
Answer: Option A. -> friction
Answer: (a).friction
Question 9. The equivalent penetration resistance is given by ___________
  1.    Nₑ=15+\(\frac{1}{2}\)(N+15)
  2.    Nₑ=\(\frac{1}{2}\)(N-15)
  3.    Nₑ=15+\(\frac{1}{2}\)(N-15)
  4.    Nₑ=15+\(\frac{1}{2}\)(N)
 Discuss Question
Answer: Option C. -> Nₑ=15+\(\frac{1}{2}\)(N-15)
Answer: (c).Nₑ=15+\(\frac{1}{2}\)(N-15)
Question 10. ______ is developed in reinforcement.
  1.    Friction
  2.    Tension
  3.    Compression
  4.    Shear
 Discuss Question
Answer: Option B. -> Tension
Answer: (b).Tension

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