Quantitative Aptitude
SIMPLIFICATION MCQs
Simplication
Suppose the man works overtime for x hours.
Now, working hours in 4 weeks = (5 x 8 x 4) = 160.
160 x 2.40 + x x 3.20 = 432
3.20x = 432 - 384 = 48
x = 15.
Hence, total hours of work = (160 + 15) = 175.
Let total number of children be x.
Then, x \(\times\frac{1}{8}x = \frac{x}{2}\times16\Leftrightarrow x = 64.\)
Therefore Number of notebooks = \(\frac{1}{8}x^{2} = \left(\frac{1}{8}\times64\times64\right) = 512\)
Let the number of hens be x and the number of cows be y.
Then, x + y = 48 .... (i)
and 2x + 4y = 140 x + 2y = 70 .... (ii)
Solving (i) and (ii) we get: x = 26, y = 22.
Therefore The required answer = 26.
Given exp. = \(\frac{(a+b)^{2}-(a-b)^{2}}{(ab)}\)
= \(\frac{4ab}{ab}\)
= 4 (where a = 469, b = 174.)
David gets on the elevator at the 11th floor of a building and rides up at the rate of 57 floors per minute. At the same time, Albert gets on an elevator at the 51st floor of the same building and rides down at the rate of 63 floors per minute. If they continue travelling at these rates, then at which floor will their paths cross ?
Suppose their paths cross after x minutes.
Then, 11 + 57x = 51 - 63x \(\Leftrightarrow\) 120x = 40
x = \(\frac{1}{3}\)
Number of floors covered by David in (1/3) min. = \(\left(\frac{1}{3}\times57\right) = 19.\)
So, their paths cross at (11 +19) i.e., 30th floor.