R = 100 I / PT => R = (100 * 7200)/ (12000 * 5) = 12% CI = P{ [1 + R /100]n - 1} = 12000 { [ 1 + 12 / 100]2 - 1} = Rs.3052.80
When compounded annually, interest = 12000[1 + 20/100]1 - 12000 = Rs.2400 When compounded semi-annually, interest = 12000[1 + 10/100]2 - 12000 = Rs.2520 Required difference = 2520 - 2400 = Rs.120
Principal = (100 * 4016.25) / (9 * 5) = Rs. 8925.
Let the sum be Rs. x. Then,
[(x * 6 * 3)/100] + [(x * 9 * 5)/100] + [(x * 13 * 3)/100] = 816018x + 45x + 39x = (8160 * 100)102x = 816000 => x = 8000.
Let the principal be P and rate of interest be R%.Required ratio = [(P * R * 6)/100] / [(P * R * 9)/100] = 6PR/9PR = 6/9 = 2:3
S.I. = (956 - 800) = Rs. 156.Rate = (100 * 156) / (800 * 3) = 6 1/2 %Now rate = (6 1/2 + 4) = 10 1/2 %New S.I. = (800 * 21/2 * 3/100) = Rs. 252New amount = (800 + 252) = Rs. 1052.
We need to know the S.I., principal and time to find the rate. Since the principal is not given, so data is inadequate.
Let the sum be Rs. 100. Then,S.I. for first 6 months = (100 * 10 *1) / (100 * 2) = Rs. 5S.I. for last 6 months = (105 * 10 * 1) / (100 * 2) = Rs. 5.25So, amount at the end of 1 year = (100 + 5 + 5.25) = Rs. 110.25Effective rate = (110.25 - 100) = 10.25%.
S.I for 5 years = (1020 - 720) = Rs. 300.S.I. for 2 years = 300/5 * 2 = Rs. 120.Principal = (720 - 120) = Rs. 600.
Let sum = x. Then, S.I. = x.
Rate = (100 * S.I.) / (P * T) = (100 * x) / (x * 12)= 25/3 = 8 1/3 %