Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
What is the rate of compound interest?
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
An amount of money was lent for 3 years. What will be the difference between the simple and the compound interest earned on it at the same rate?
P = Rs 16000, R = (10/2)%
per quarter, t = 3 quarters
C.I = Rs [16000 × (1+ 5/100)3-16000)
= Rs [16000 × 21/20 ×21/20× 21/20- 16000)
=Rs (18522-16000)=Rs 2522
Let the principal be Rs x.
Then
X × (1 + 10/100)3 “ x = 331
=> (x × 11/10 × 11/10 × 11/10 - x) = 331
=> ((1331x-1000x)/1000) = 331
=> 331x = 331000
=> X = 1000
Hence the principal is Rs 1000
Let principal be Rs x and the rate is R % p.a.
Then X × (1 + R/100)5 = 2x
=> (1 + R/100) 5 = 2
Let x × (1 + R/100) t = 8x
=> (1 + R/100) t = 8 = 23
={(1 + R/100) 5 }3
=> (1 + R/100) t = (1 + R/100) 15
=> T = 15 Years
Let the sum be Rs x.
Then
S. I = Rs (x × 8/100 × 2) = Rs 4x/25
C. I = Rs [x × (1 + 8/100)2 - x]
= Rs (x × 27/25 × 27/25 - x)
=Rs 104x/625
(C.I) “ (S.I)
= Rs(104x/625 “ 4x /25)
= Rs 4x /625
Therefore 4x/625 = 768
=> x = ((768 ×625)/4) = 120000
Therefore sum = Rs 120000
Amount = Rs[10000 × (1 + 4/100) × (1 +5/100) × (1 × 6/100)]
= Rs(1000 × 26/25 × 21/20 × 53/50)
= Rs (57876/5) = Rs 11575.20
C.I = Rs (11575.20 - 10000) = Rs 1575.20
Let the money borrowed be Rs x
Interest paid by the money lender = Rs (x × 4/100 × 1) =Rs x/25
Interest received by the money lender
= Rs [x × (1 + 3/100)2 - x]
= Rs(x × 103/100 × 103/100 - x)
Gain = Rs (609x/1000 “ x /25)
= Rs 209x/1000 = Rs 609x/10000
Therefore 209x/10000 = 104.50
=> 209x = 1045000
=> x = 5000
Hence money borrowed = Rs 5000
S.I = Rs (6000 × 5/100 × 2) = Rs 600
C.I = Rs [5000 × (1 + 8/100)2 - 5000]
= Rs (5000 × 27/25 × 27/25 - 5000)
= Rs(5832 - 5000)
= Rs 832
(C.I) “ (S.I) = Rs (832 - 600) = Rs 232
P = Rs 20000, A =Rs 24200,
t = 2 years
20000 × (1 + R/100)2 = 24200
=> (1 + R/100) 2 = 24200/20000 = 121/100 = (11/10) 2
=> 1 + R/100 = 11/10
=> R/100 = (11/10 - 1) = 1/10
=> R = (100 × 1/10) % p.a = 10 % p.a
Hence, Rate = 10 % p.a