Let the parts be `x, y and (2379 - (x + y)]`

`x + (x xx 2 xx 5/100) =  y + (y xx 3 xx 5/100) =  z + (z xx 4 xx 5/100)`

`rArr      (11x)/(10)  =  (23y)/(20)  = (6z)/(5)  = k`

`rArr      x = (10k)/(11),    y = (20k)/(23),      z = (5k)/(6)`

But   `x + y + z`  = 2379

`rArr   (10k)/(11) + (20k)/(23) + (5k)/(6)  = 2379`

`rArr     1380k + 1320k + 1265k =  2379 xx 11 xx 23 xx 6`

`rArr      k = (2379 xx 11 xx 23 xx 6)/(3965) =  (3 xx 11 xx 23 xx 6)/(5)`

`:.`  `  x = (10/11 xx (3 xx 11 xx 23 xx 6)/(5))` =  828.

Hence , the first part is Rs. 828 .

Let the part be `x, y and [2600 - (x + y)]`. Then

`(x xx 4 xx 1)/(100) = (y xx 6 xx 1)/(100) = ([2600 - (x + y)] xx 8 xx 1)/(100)`

`:.`      `y/x = 4/6 = 2/3 or y = 2/3 y`

So    ` (x xx 4 xx 1)/(100) = ((2600 - 5/3 x) xx 8)/(100)`

`hArr      4x = ((7800 - 5x) xx 8)/(3)`

`hArr      52x = (7800 xx 8)`

`hArr       x =  ((7800 xx 8)/(52)`

`hArr       x =  1200`

`:.`        Money invested at 4%  = Rs. 1200.

Let `x, y and z` be the amounts invested in schemes A, B and C respecivelt, Then ,

`((x xx 10 xx 1)/(100)) + ((y xx 12 xx 1)/(100)) + ((z xx 15 xx 1)/(100)) = 3200`

`hArr      10x + 12y + 15z = 320000`...................................................(i)

Now ,    z = 240%   of y = `12/5 y` ......................................................(ii)

And,       z = 150% of `x =  3/2 x`   `rArr    x = 2/3 z = (2/3 xx 12/5)y = 8/5 y`  .............................(iii)

From  (i), (ii) and (iii), we have .

16y + 12y + 36y =  320000    

`hArr      64y =  320000            hArr       y = 5000`

`:.`        Sum invested in scheme  B = Rs 5000.

Let the sum invested at 9% be  Rs. `x` and  that invested a 11%  be Rs.` 100000- x)`

Then , `((x xx 9 xx 1)/(100) + [((100000 - x) xx 11 xx 1)/(100)]` =  `(100000 xx 39/4 xx 1/100)`

`hArr      (9x + 1100000 - 11x)/(100) =  39000/4` =  9750

`hArr      2x = (1100000 - 975000) =  125000       hArr     x = 62500`

`:.`      Sum invested at 9%  = Rs. 62500

          Sum invesed at 11 % =  Rs. (100000 - 62500) =   Rs. 37500

Let he required rate be R ,  Then ,

`((2000 xx 8 xx 1)/(100)) + (4000 xx 15/2 xx 1/100) + (1400 xx 17/2 xx 1/100)` + `(2600 xx R xx 1/100)= (813/10000 xx10000)`

`hArr     160 + 300 + 119 + 26R =  813`

`hArr     R = 9`

Let the sum lent at  5% be Rs. `x` and that lent at 8% be Rs. (1550 - `x`). Then

`((x xx 5 xx 3)/(100)) + [((1550 - x) xx 8 xx 3)/(100)] = 300`

`hArr    15x - 24x + (1550 xx 24) = 30000`

`hArr   9x =  7200`

`hArr     x =  800`

`:.`        Required  ratio  = 800 : 750 =    16 : 15

Let the sum lent at 10% be Rs. `x` and that lent at 9% be Rs. (2600 - `x`),

Then     `((x xx 10 xx 5)/(100)) =  ((2600 - x) xx 9 xx 6)/(100)`

`hArr     50x = (2600 xx 54)  -  54x      rArr        x = ((2600 xx 54)/(104))` = 1350

`:.`        Sum lent at   10%  = Rs. 1350.

Let the sum invested in scheme A be Rs. `x` and that in Scheme B be Rs. (13900 - `x`).

Then,`((x xx 14 xx 2)/(100)) + [((13900 - x) xx 11 xx 2)/(100)] = 3508`

`hArr      28x - 22x = 350800 - (13900 xx 22)`

`hArr     6x =  45000`

`hArr     x = 7500`

So, sum invested in Scheme B  = Rs. (13900 - 7500) =  Rs.  6400

Let the sum be Rs. `x` , rate be R% p.a. and time be T years.

Then ,`[(x xx (R + 2) xx )/(100)] - ((x xx R xx T)/(100)) = 108`        `hArr   2xT     = 10800`................................(i)

And ,` [(x xx R xx (T + 2))/(100)] - ((x xx R xx T)/(100)) = 180 `       `hArr     2xT   = 18000.`.................................(ii)

Clearly , from (i) and (ii) , we cannot find the value of `x` 

So, he data is inadequate.

Money paid in cash = Rs. 1000.

Balance payment  = Rs. (20000 - 1000) = Rs. 19000