Let the parts be x, y and [2600 - (x + y)].Then,(x * 4 * 1)/100 = (y * 6 * 1)/100 = {[2600 - (x + y)] * 8 * 1}/100y/x = 4/6 = 2/3 or y = 2/3 xSo, (x * 4 * 1)/100 = [(2600 - 5/3 x) * 80/10052x = (7800 * 8) => x = 1200Money invested at 4% = Rs. 1200.
Let the parts be x, y and [2379 - (x + y)]x + (x * 2 * 5/100) = y + (y * 3 * 5/100) = z + (z * 4 * 5/100)11x/10 = 23y/20 = 6z/5 = kx = 10k/11, y = 20k/23, z = 5k/6But x + y + z = 237910k/11 + 20k/23 + 5k/6 = 2379k = (2379 * 11 * 23 * 6)/3965 = (3 * 11 * 23 * 6)/5x = [10/11 * (3 * 11 * 23 * 6)/5] = 828Hence, the first part is Rs. 828.
Let x, y and z be the amount invested in schemes A, B and C respectively. Then, (x * 10 * 1)/100 + (y * 12 * 1)/100 + (z * 15 * 1)/100 = 320010x + 12y + 15z = 320000Now, z = 240% of y = 12/5 yAnd, z = 150% of x = 3/2 xx = 2/3 z = ( 2/3 * 12/5) y = 8/5 y16y + 12y + 36y = 320000y = 5000Sum invested in scheme B = Rs. 5000.
S.I for 3 years = Rs. (2600-2240) = Rs. 360
S.I for 2 years = Rs. (360/3 × 2) = Rs. 240.
Sum = Rs. (2240-240) = Rs. 2000.
S.I for 3 years = Rs. (1350-1260) = Rs. 90
S.I for 2 years = Rs (90/3 × 2) = Rs. 60
Sum = Rs. (1260-60) = Rs. 1200
Rate = 6000/2400 = 2.5%
Rate = x % per annum = 90
(or)
18x = 90
or x = 5