Quantitative Aptitude
RATIO AND PROPORTION MCQs
Ratio & Proportion, Ratio, Proportion
Let A = 2k, B = 3k and C = 5k.
A's new salary = \(\frac{115}{100} of 2k = \left(\frac{115}{100}\times2k\right) = \frac{23k}{10}\)
B's new salary = \(\frac{110}{100} of 3k = \left(\frac{110}{100}\times3k\right) = \frac{33k}{10}\)
C's new salary = \(\frac{120}{100} of 5k = \left(\frac{120}{100}\times5k\right) = 6k
\)
Therefore New ratio \(\left(\frac{23k}{10}:\frac{33k}{10}:6k\right) = 23:33:60\)
Let 40% of A = \(\frac{2}{3}B\)
Then,\(\frac{40A}{100}= \frac{2B}{3} \)
\(\frac{2A}{5}=\frac{2B}{3}\)
\(\frac{A}{B} = \left(\frac{2}{3}\times\frac{5}{2}\right)= \frac{5}{3} \)
Therefore A : B = 5 : 3.
Let the fourth proportional to 5, 8, 15 be x.
Then, 5 : 8 : 15 : x
\(\Rightarrow\) 5x = (8 x 15)
X = \(\frac{(8\times15)}{5}\) = 24
Let the numbers be 3x and 5x.
Then, \(\frac{3x-9}{5x-9} = \frac{12}{23}\)
\(\Rightarrow\) 23(3x - 9) = 12(5x - 9)
\(\Rightarrow\) 9x = 99
\(\Rightarrow\) x = 11.
Therefore The smaller number = (3 x 11) = 33.
Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.
Then, sum of their values = Rs. \(\left(\frac{25x}{100}\times\frac{10\times2x}{100}\times\frac{5\times3x}{100}\right) = Rs.\frac{60x}{100} \)
Therefore \(\frac{60x}{100} =30 \Leftrightarrow \frac{30\times100}{60} = 50\)
Hence, the number of 5 p coins = (3 x 50) = 150.
 - a:b=5:9 and b:c=4:7
= (4x9/4): (7x9/4) = 9:63/4
a:b:c = 5:9:63/4 =20:36:63
 - Let the fourth proportional to 4, 9, 12 be a.
Then, 4 : 9 : : 12 : a
4 a =9 x 12
a=(9 x 12)/14=27;
Fourth proportional to 4, 9, 12 is 27
 - x/y=3/4
(4x+5y)/(5x+2y)= (4( x/y)+5)/(5 (x/y)-2)
=(4(3/4)+5)/(5(3/4)-2)
=(3+5)/(7/4)=32/7
 - Sum of ratio terms = (5 + 3) = 8.
First part = Rs. (672 x (5/8)) = Rs. 420;
Second part = Rs. (672 x (3/8)) = Rs. 252
- Sum of ratio terms = (35 + 28 + 20) = 83.
A's share = Rs. (1162 x (35/83))= Rs. 490;
B's share = Rs. (1162 x(28/83))= Rs. 392;
C's share = Rs. (1162 x (20/83))= Rs. 280
To divide Rs. 1162 among A, B, C in the ratio of 35 : 28 : 20, we need to use the following steps:
• Find the total ratio, which is the sum of the individual ratios. In this case, the total ratio is 35 + 28 + 20 = 83.
• Now divide the total amount of Rs. 1162 by the total ratio, i.e. 1162/83 = 14.
• Multiply the individual ratios with the result of the previous step, i.e.
• For A, 35 x 14 = 490
• For B, 28 x 14 = 392
• For C, 20 x 14 = 280
Therefore, the required division of Rs. 1162 among A, B, C in the ratio of 35 : 28 : 20 is 490, 392 and 280 respectively.
Hence, Option C is the correct answer.
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