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Quantitative Aptitude

RATIO AND PROPORTION MCQs

Ratio & Proportion, Ratio, Proportion

Total Questions : 895 | Page 7 of 90 pages
Question 61.

The salaries A, B, C are in the ratio 2 : 3 : 5. If the increments of 15%, 10% and 20% are allowed respectively in their salaries, then what will be new ratio of their salaries?

  1.    3 : 3 : 10
  2.    10 : 11 : 20
  3.    23 : 33 : 60
  4.    Cannot be determined
 Discuss Question
Answer: Option C. -> 23 : 33 : 60

Let A = 2k, B = 3k and C = 5k.


A's new salary = \(\frac{115}{100} of 2k = \left(\frac{115}{100}\times2k\right) = \frac{23k}{10}\)


B's new salary = \(\frac{110}{100} of 3k = \left(\frac{110}{100}\times3k\right) = \frac{33k}{10}\)


C's new salary = \(\frac{120}{100} of 5k = \left(\frac{120}{100}\times5k\right) = 6k
\)


Therefore  New ratio \(\left(\frac{23k}{10}:\frac{33k}{10}:6k\right) = 23:33:60\)

Question 62.

If 40% of a number is equal to two-third of another number, what is the ratio of first number to the second number?

  1.    2 : 5
  2.    3 : 7
  3.    5 : 3
  4.    7 : 3
 Discuss Question
Answer: Option C. -> 5 : 3

Let 40% of A = \(\frac{2}{3}B\)


Then,\(\frac{40A}{100}= \frac{2B}{3} \)


\(\frac{2A}{5}=\frac{2B}{3}\)


\(\frac{A}{B} = \left(\frac{2}{3}\times\frac{5}{2}\right)= \frac{5}{3} \)


Therefore A : B = 5 : 3.

Question 63.

The fourth proportional to 5, 8, 15 is:

  1.    18
  2.    24
  3.    19
  4.    20
 Discuss Question
Answer: Option B. -> 24

Let the fourth proportional to 5, 8, 15 be x.


Then, 5 : 8 : 15 : x


\(\Rightarrow\) 5x = (8 x 15)


X = \(\frac{(8\times15)}{5}\) = 24

Question 64.

Two number are in the ratio 3 : 5. If 9 is subtracted from each, the new numbers are in the ratio 12 : 23. The smaller number is:

  1.    27
  2.    33
  3.    49
  4.    55
 Discuss Question
Answer: Option B. -> 33

Let the numbers be 3x and 5x.


Then, \(\frac{3x-9}{5x-9} = \frac{12}{23}\)


 \(\Rightarrow\) 23(3x - 9) = 12(5x - 9)


\(\Rightarrow\) 9x = 99


\(\Rightarrow\) x = 11.


Therefore The smaller number = (3 x 11) = 33.

Question 65.

In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is Rs. 30 in all, how many 5 p coins are there?

  1.    50
  2.    100
  3.    150
  4.    200
 Discuss Question
Answer: Option C. -> 150

Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.


Then, sum of their values = Rs. \(\left(\frac{25x}{100}\times\frac{10\times2x}{100}\times\frac{5\times3x}{100}\right) = Rs.\frac{60x}{100} \)


Therefore  \(\frac{60x}{100} =30 \Leftrightarrow \frac{30\times100}{60} = 50\)


Hence, the number of 5 p coins = (3 x 50) = 150.

Question 66.

If a : b = 5 : 9 and b : c = 4: 7, find a : b : c?

  1.    20:36:63
  2.    20:63:36
  3.    63:20:36
  4.    36:63:20
  5.    None of these
 Discuss Question
Answer: Option A. -> 20:36:63
 -  a:b=5:9 and b:c=4:7
= (4x9/4): (7x9/4) = 9:63/4
a:b:c = 5:9:63/4 =20:36:63
Question 67.

Find the fourth proportional to 4, 9, 12?

  1.    24
  2.    21
  3.    27
  4.    36
  5.    None of these
 Discuss Question
Answer: Option C. -> 27
 -  Let the fourth proportional to 4, 9, 12 be a.
Then, 4 : 9 : : 12 : a
4 a =9 x 12
a=(9 x 12)/14=27;
Fourth proportional to 4, 9, 12 is 27
Question 68.

If x : y = 3 : 4, find (4x + 5y) : (5x - 2y)?

  1.    23/7
  2.    32/7
  3.    23/7
  4.    21/6
  5.    None of these
 Discuss Question
Answer: Option B. -> 32/7
 -  x/y=3/4
(4x+5y)/(5x+2y)= (4( x/y)+5)/(5 (x/y)-2)
=(4(3/4)+5)/(5(3/4)-2)
=(3+5)/(7/4)=32/7
Question 69.

Divide Rs. 672 in the ratio 5 : 3?

  1.    420 and 252
  2.    410 and 246
  3.    400 and 240
  4.    440 and 264
  5.    None of these
 Discuss Question
Answer: Option A. -> 420 and 252
 -  Sum of ratio terms = (5 + 3) = 8.
First part = Rs. (672 x (5/8)) = Rs. 420;
Second part = Rs. (672 x (3/8)) = Rs. 252
Question 70.

Divide Rs. 1162 among A, B, C in the ratio 35 : 28 : 20?

  1.    480 , 382 and 300
  2.    490, 280 and 382
  3.    490 , 392 and 280
  4.    392 , 490 and 280
  5.    None of these
 Discuss Question
Answer: Option C. -> 490 , 392 and 280

 -  Sum of ratio terms = (35 + 28 + 20) = 83.
A's share = Rs. (1162 x (35/83))= Rs. 490;
B's share = Rs. (1162 x(28/83))= Rs. 392;
C's share = Rs. (1162 x (20/83))= Rs. 280

To divide Rs. 1162 among A, B, C in the ratio of 35 : 28 : 20, we need to use the following steps:

Find the total ratio, which is the sum of the individual ratios. In this case, the total ratio is 35 + 28 + 20 = 83.

Now divide the total amount of Rs. 1162 by the total ratio, i.e. 1162/83 = 14.

Multiply the individual ratios with the result of the previous step, i.e.

For A, 35 x 14 = 490
For B, 28 x 14 = 392
For C, 20 x 14 = 280

Therefore, the required division of Rs. 1162 among A, B, C in the ratio of 35 : 28 : 20 is 490, 392 and 280 respectively.

Hence, Option C is the correct answer.

If you think the solution is wrong then please provide your own solution below in the comments section .

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