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Quantitative Aptitude

RATIO AND PROPORTION MCQs

Ratio & Proportion, Ratio, Proportion

Total Questions : 895 | Page 4 of 90 pages
Question 31.

  1. 96 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smaller part.

  1.    42
  2.    44
  3.    46
  4.    48
 Discuss Question
Answer: Option A. -> 42
Question 32.

  1. 75 kg of an alloy A is mixed with 100 kg of alloy B. In alloy A, lead and tin are in the ratio of 2 : 3 and alloy B has tin and copper in the ratio of 3 : 7, then the amount (in kg) of tin in the new alloy is

  1.    65 kg
  2.    75 kg
  3.    85 kg
  4.    none of these
 Discuss Question
Answer: Option B. -> 75 kg
Question 33.
  1. 40% of a man’s daily output is equal to 60% of a second man’s daily output. If the first man turns out 1440 toys everyday, the second man’s output in terms of number of toys is

  1.    900
  2.    930
  3.    960
  4.    none of these
 Discuss Question
Answer: Option C. -> 960
Let's denote the first man's daily output as x and the second man's daily output as y.According to the question, we have:
  • 40% of x = 60% of y
  • x = 1440
Using the second equation, we can solve for x as:x = 1440
Substituting x in the first equation, we get:0.4 * 1440 = 0.6 * y
Simplifying, we get:576 = 0.6 * y
Dividing both sides by 0.6, we get:y = 960
Therefore, the second man's output in terms of the number of toys is 960.
Formula:
  • Percentage = (Part/Whole) * 100
Key Points:
  • To solve the problem, we need to use the formula for percentage.
  • We can solve for one of the variables by using the given information, and then use that value to solve for the other variable.
  • In this case, we can solve for x using the given value and then use that value to solve for y.

If you think the solution is wrong then please provide your own solution below in the comments section .
Question 34.
  1. A sum is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paise and Z gets 30 paise. If the share of Y is Rs 27, what is the total amount?

  1.    Rs. 95
  2.    Rs. 105
  3.    Rs. 105
  4.    none of these
 Discuss Question
Answer: Option C. -> Rs. 105
Let the amount X gets be Rs. x.
Then, Y gets 45/100 of x = 9/20 of x and Z gets 30/100 of x = 3/10 of x.
Given, Y gets Rs. 27.
So, 9/20 of x = 27
⇒ x = (27 × 20)/9 = Rs. 60
Total amount = Rs. (x + 9/20x + 3/10x) = Rs. (60 + 27 + 18) = Rs. 105
Therefore, the correct answer is option C) Rs. 105.
Key takeaways and formulas:
  • In a ratio distribution problem, the sum of the ratios is the total number of parts. For instance, in this problem, the sum of the ratios is 1 + 45/100 + 30/100 = 1.75, which means there are 1.75 parts in total.
  • To find the share of each person, we multiply the total amount by the ratio they get. For example, if X gets x, then Y gets (45/100)x and Z gets (30/100)x.
  • We can also use proportions to solve the problem. For example, if Y gets Rs. 27, we can set up the proportion (45/100)x/((9/20)x) = 27/1 and solve for x.
  • The total amount is the sum of the individual shares, which is x + (45/100)x + (30/100)x.
Question 35.
  1. Rs 160 contained in a box consists of one rupee, 50 paisa and 25 paisa coins in the ratio of 4 : 5 : 6. What is the number of 25 paisa coins?

  1.    100
  2.    110
  3.    120
  4.    130
 Discuss Question
Answer: Option C. -> 120

The given box contains a total of 160 Rupees and the ratio of one rupee, 50 paisa and 25 paisa coins is 4:5:6.
Let us assumex number of one rupee coins,y number of 50 paisa coins andz number of 25 paisa coins, then the equation can be written as:
1x + 0.50y + 0.25z = 160
We can rewrite the equation as 4x + 5y + 6z = 800
Now, we can solve the equation using the expressions of x, y, and z
x + 2y + 4z = 400
On solving, we get
x = 400 2y 4z
Substituting the value of x in 4x + 5y + 6z = 800
400 + 5y + 6z = 800
5y + 6z = 400
On solving, we get
y + 2z = 80
Substituting the value of y in x + 2y + 4z = 400
400 2(80-2z) 4z = 400
8z = 320
On solving, we get
z = 40
Therefore, the required number of 25 paisa coins is 40.
Hence, the correct answer is Option C.

If you think the solution is wrong then please provide your own solution below in the comments section .

Question 36.

  1. A box contains Rs 56 in the form of coins of one rupee, 50 paise and 25 paise. The number of 50-paise coins is double the number of 25 paise coins and four times the number of one rupee coins. How many 50 paise coins are there in the box?

  1.    44
  2.    54
  3.    64
  4.    none of these
 Discuss Question
Answer: Option C. -> 64
Question 37.

  1. In a school, 20% of boys are same in number as  \(\frac{1}{3}\)  rd of the girls and 25% of the girls are same in number as    \(\frac{3}{20}\)  th of the boys. Find the ratio of boys to girls in that school.

  1.    3: 5
  2.    5 : 3
  3.    3 : 4
  4.    4 :3
 Discuss Question
Answer: Option B. -> 5 : 3
Question 38.

  1. Two numbers are in the ratio of 6 : 7 and the product of their L.C.M. and H.C.F. is 9450. The sum of the numbers is

  1.    175
  2.    185
  3.    195
  4.    none of these
 Discuss Question
Answer: Option C. -> 195
Question 39.

  1. The ages of Rita and Mita are in the ratio of 4 : 5. Twenty years hence, their ratio of ages would be 6 : 7. Their present ages (in years) are

  1.    24 : 30
  2.    28 : 32
  3.    40 : 50
  4.    none of these
 Discuss Question
Answer: Option C. -> 40 : 50
Question 40.

  1. A wallet contains one rupee, 50 paise, 25 paise and 20 paise coins in the ratio of 1 : 2 : 3 : 4. If the total value of the coins is Rs 710, then the number of 20 paise coins exceeds that of 25 paise coins by

  1.    150
  2.    200
  3.    250
  4.    300
 Discuss Question
Answer: Option B. -> 200

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