Quantitative Aptitude
AGES MCQs
Problems On Ages
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4xyears.
Therefore (4x + 8) = \(\frac{5}{2}\left(x+8\right)\)
8x + 16 = 5x + 40
3x = 24
x = 8.
Hence, required ratio = \(\frac{(4x+16)}{(x+16)}\) = \(\frac{48}{24}\) = 2.
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.
Let the son's present age be x years. Then, (38 - x) = x
2x = 38.
x = 19.
Therefore Son's age 5 years back (19 - 5) = 14 years.
Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.
Therefore (2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, B's age = 2x = 10 years.
Let the present ages of Sameer and Anand be 5x years and 4x years respectively.
Then, \(\frac{5x+3}{4x+3} = \frac{11}{9}\)
9(5x + 3) = 11(4x + 3)
45x + 27 = 44x + 33
45x - 44x = 33 - 27
x = 6.
Therefore Anand's present age = 4x = 24 years.
Let the son's present age be x years. Then, man's present age = (x + 24) years.
Threrefore (x + 24) + 2 = 2(x + 2)
x + 26 = 2x + 4
x = 22.
Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.
Then, \(\frac{(6x+6)+4}{(5x+6)+4} = \frac{11}{10}\)
10(6x + 10) = 11(5x + 10)
5x = 10
x = 2.
So Sagar's present age = (5x + 6) = 16 years.
Let the present ages of son and father be x and (60 -x) years respectively.
Then, (60 - x) - 6 = 5(x - 6)
54 - x = 5x - 30
6x = 84
x = 14.
So Son's age after 6 years = (x+ 6) = 20 years..
Let the present ages of Arun and Deepak be 4x years and 3x years respectively. Then,
4x + 6 = 26 \(\Leftrightarrow\) 4x = 20
x = 5.
Therefore Deepak's age = 3x = 15 years.
Let Rahul's age be x years.
Then, Sachin's age = (x - 7) years.
So, \(\frac{x-7}{x} = \frac{7}{9}\)
9x - 63 = 7x
2x = 63
x = 31.5
Hence, Sachin's age =(x - 7) = 24.5 years.