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MCQs

Total Questions : 50 | Page 1 of 5 pages
Question 1. Usually while designing what is the range of depth of the aerated grit chamber assumed?
  1.    0.5-2 m
  2.    8-10 m
  3.    2-5 m
  4.    12 m
 Discuss Question
Answer: Option C. -> 2-5 m
Answer: (c).2-5 m
Question 2. Aerated grit chambers are usually designed to remove particles in which range of size?
  1.    0.1mm diameter
  2.    0.35 mm diameter
  3.    0.21 mm diameter
  4.    0.41 mm diameter
 Discuss Question
Answer: Option C. -> 0.21 mm diameter
Answer: (c).0.21 mm diameter
Question 3. Usually while designing what is the range of length of the aerated grit chamber assumed?
  1.    7.5-20
  2.    4-6 m
  3.    25 m
  4.    50 m
 Discuss Question
Answer: Option A. -> 7.5-20
Answer: (a).7.5-20
Question 4. Usually while designing what is the range of the width of the aerated grit chamber assumed?
  1.    0.5-2 m
  2.    8-10 m
  3.    2.5-7.0m
  4.    12m
 Discuss Question
Answer: Option C. -> 2.5-7.0m
Answer: (c).2.5-7.0m
Question 5. What is the amount of grit quantities captured by the aerated grit chamber?
  1.    0.004-0.20 m³/10³.m³
  2.    0.25 m³/10³.m³
  3.    <0.004 m³/10³.m³
  4.    0.5 m³/10³.m³
 Discuss Question
Answer: Option A. -> 0.004-0.20 m³/10³.m³
Answer: (a).0.004-0.20 m³/10³.m³
Question 6. Which of these screens is used to remove secondary suspended solids?
  1.    Medium drum rotary screen
  2.    Fine drum rotary screen
  3.    Tangential fine screen
  4.    Horizontal reciprocating screen
 Discuss Question
Answer: Option B. -> Fine drum rotary screen
Answer: (b).Fine drum rotary screen
Question 7. What is the mathematical representation of hydraulic loses through a screen?
  1.    hL= 1/C(V²/2g)
  2.    hL= 1/C(V²-v²/2g)
  3.    hL= 1/C(V²-v²/g)
  4.    hL= 1/C(V²/g)
 Discuss Question
Answer: Option B. -> hL= 1/C(V²-v²/2g)
Answer: (b).hL= 1/C(V²-v²/2g)
Question 8. What is the amount of BOD removed by a fixed parabolic fine screen?
  1.    25-40 %
  2.    40-50%
  3.    5-20%
  4.    30-40%
 Discuss Question
Answer: Option C. -> 5-20%
Answer: (c).5-20%
Question 9. How is the headloss for a fine screen calculated?
  1.    hL= 1/2g(Q/CA)²
  2.    hL= 1/g(Q/CA)²
  3.    hL= 1/2g(Q/C)²
  4.    hL= 1/2g(Q/CA)
 Discuss Question
Answer: Option A. -> hL= 1/2g(Q/CA)²
Answer: (a).hL= 1/2g(Q/CA)²
Question 10. What is the headloss for fine screens?
  1.    0.8-1.4m
  2.    2-2.5m
  3.    3-3.5m
  4.    <0.8 m
 Discuss Question
Answer: Option A. -> 0.8-1.4m
Answer: (a).0.8-1.4m

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