5th Grade > Mathematics
PLAYING WITH NUMBERS MCQs
Total Questions : 40
| Page 1 of 4 pages
Answer: Option A. -> ÷, ×, + −
:
A
Brackets
Of
Division
Multiplication
Addition
Subtraction
According to BODMAS, Division (÷), is done before Multiplication (×), which is followed by Addition (+) & and then by Subtraction (−).
:
A
Brackets
Of
Division
Multiplication
Addition
Subtraction
According to BODMAS, Division (÷), is done before Multiplication (×), which is followed by Addition (+) & and then by Subtraction (−).
Answer: Option D. -> 10 thousands
:
D
55555÷5
= 555555
= 11111
Now,
=11111−1111––––––––10,000––––––––=10thousands
:
D
55555÷5
= 555555
= 11111
Now,
=11111−1111––––––––10,000––––––––=10thousands
Answer: Option B. -> 4040404
:
B
4040404 doubled means multipliedby 2.
4040404×2–––––––––8080808–––––––––––
8080808, when divided by 2, means it is halved.
→ 8080808÷2
= 80808082
=4040404
:
B
4040404 doubled means multipliedby 2.
4040404×2–––––––––8080808–––––––––––
8080808, when divided by 2, means it is halved.
→ 8080808÷2
= 80808082
=4040404
Answer: Option A. -> 45÷9
:
A
BODMAS = B - Brackets
O - Of
D - Division
M - Multiplication
A - Addition
S - Subtraction
The given expression is 45÷9+8×5−45
According to BODMAS, Division is done before Multiplication, Addition and Subtraction.
Hence, "45÷9" is the operation that needs to beperformed first.
:
A
BODMAS = B - Brackets
O - Of
D - Division
M - Multiplication
A - Addition
S - Subtraction
The given expression is 45÷9+8×5−45
According to BODMAS, Division is done before Multiplication, Addition and Subtraction.
Hence, "45÷9" is the operation that needs to beperformed first.
Answer: Option A. -> 11011
:
A
Two lakhs two hundred = 2,00,200
When 2,00,200 is subtracted from 2,22,222, we have:
2,22,222−2,00,200–––––––––––––22022––––––––––––
When 22022 is divided by 2, we get:
220222=11011
:
A
Two lakhs two hundred = 2,00,200
When 2,00,200 is subtracted from 2,22,222, we have:
2,22,222−2,00,200–––––––––––––22022––––––––––––
When 22022 is divided by 2, we get:
220222=11011
Answer: Option C. -> 59
:
C
Applying Distributive property of multiplication over addition to simplify:
(18×50)+(18×9)
=18×(50+9)=18×59
:
C
Applying Distributive property of multiplication over addition to simplify:
(18×50)+(18×9)
=18×(50+9)=18×59
Answer: Option D. -> 83
:
D
15×7=105
15+7=22
105−22–––––83
105 is 83 more than 22.
:
D
15×7=105
15+7=22
105−22–––––83
105 is 83 more than 22.
Answer: Option C. -> 18
:
C
Number of children in class 5 = 43
Number of children in class 6 = 29
Total number of children = 43+29=72
Number of buses = 4
Number of children in each bus
= 72÷4
18472−4–232−32–––0Therefore, number of children in each bus is 18.
:
C
Number of children in class 5 = 43
Number of children in class 6 = 29
Total number of children = 43+29=72
Number of buses = 4
Number of children in each bus
= 72÷4
18472−4–232−32–––0Therefore, number of children in each bus is 18.
Answer: Option A. -> 50 Tens 5 ones
:
A
50 Tens 5 Ones = 50×10+5×1=500+5=505
4 Hundreds, 9 Tens9 Ones = 4×100+9×10+9×1=400+90+9=499
505>499
Hence, 50 Tens5 Ones is greater.
:
A
50 Tens 5 Ones = 50×10+5×1=500+5=505
4 Hundreds, 9 Tens9 Ones = 4×100+9×10+9×1=400+90+9=499
505>499
Hence, 50 Tens5 Ones is greater.
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