7th Grade > Mathematics
AREA AND PERIMETER MCQs
Perimeter And Area
Total Questions : 99
| Page 1 of 10 pages
Answer: Option A. -> Sq. m
:
A
The metreis the SI unit and hence, sq. m is in the SI units of area.
:
A
The metreis the SI unit and hence, sq. m is in the SI units of area.
Answer: Option B. -> 8 cm
:
B
Area of a square =Side × Side
⇒Side × Side = 64 cm2
When we look at the factors of 16,
64 = 64 x 1
64 = 32 x 2
64 = 16 x 4
64 = 8 x 8
Since the sides have to be equal, it has to be 8 cm long as 8 ×8 = 64
∴ Side will be 8 cm long.
:
B
Area of a square =Side × Side
⇒Side × Side = 64 cm2
When we look at the factors of 16,
64 = 64 x 1
64 = 32 x 2
64 = 16 x 4
64 = 8 x 8
Since the sides have to be equal, it has to be 8 cm long as 8 ×8 = 64
∴ Side will be 8 cm long.
Answer: Option B. -> 10 cm2
:
B
There are 10 small squares in the given figure.
Area of the small square = 1 cm2
⇒ Area of the given figure
= 10 × Area of one square
= 10 ×1 cm2
= 10 cm2
:
B
There are 10 small squares in the given figure.
Area of the small square = 1 cm2
⇒ Area of the given figure
= 10 × Area of one square
= 10 ×1 cm2
= 10 cm2
Answer: Option D. -> dm
:
D
Decimeter is not a unit of area. Units of area are given as squared units
:
D
Decimeter is not a unit of area. Units of area are given as squared units
Answer: Option C. -> 20 cm2
:
C
Area of a rectangle = Length ×Breadth
= 4 × 5
= 20 cm2
:
C
Area of a rectangle = Length ×Breadth
= 4 × 5
= 20 cm2
Answer: Option D. -> 9 cm
:
D
Given:
The breadth of a rectangle = 7 cm
Area of the rectangle = 63 cm2
Area of a rectangle = length × breadth
63 cm2 = length × 7 cm
length=Areabreadth
=63cm27cm
=9cm
:
D
Given:
The breadth of a rectangle = 7 cm
Area of the rectangle = 63 cm2
Area of a rectangle = length × breadth
63 cm2 = length × 7 cm
length=Areabreadth
=63cm27cm
=9cm
Answer: Option C. -> 80 m
:
C
Given: Side of the Square = 10 m
Since Ali isrunningaround the park, he runsalong theboundary i.e. the perimeter of the park.
Perimeter of a square = 4 × Side
= 4 × 10 m
= 40 m
Distance covered by Ali in two rounds of the park =2 × Perimeter
= 2 × 40 m
= 80 m
:
C
Given: Side of the Square = 10 m
Since Ali isrunningaround the park, he runsalong theboundary i.e. the perimeter of the park.
Perimeter of a square = 4 × Side
= 4 × 10 m
= 40 m
Distance covered by Ali in two rounds of the park =2 × Perimeter
= 2 × 40 m
= 80 m
Answer: Option A. -> 25:36
:
A
The area grazed by both the goats will be circular in shape as they are moving at a constant distance from a fixed point.
Hence, the area grazed when a goat is tied at a point with a rope would be a circle with radius equal to the length of the rope.
Area of a circle = πr2.
Hence, the required ratio = AreaatAAreaatB
= (πrAπrB)2
=(rArB)2
= (56)2 = 25:36 .
:
A
The area grazed by both the goats will be circular in shape as they are moving at a constant distance from a fixed point.
Hence, the area grazed when a goat is tied at a point with a rope would be a circle with radius equal to the length of the rope.
Area of a circle = πr2.
Hence, the required ratio = AreaatAAreaatB
= (πrAπrB)2
=(rArB)2
= (56)2 = 25:36 .
Answer: Option A. -> 169
:
A
First of all, we have to convert all the dimensions into the same unit. ( 1 m = 100 cm )
The number of tiles × Area of each tile = Area of the entire room.
⇒ Number of tiles = 15.6×19.51.2×1.5 = 169tiles.
:
A
First of all, we have to convert all the dimensions into the same unit. ( 1 m = 100 cm )
The number of tiles × Area of each tile = Area of the entire room.
⇒ Number of tiles = 15.6×19.51.2×1.5 = 169tiles.
Answer: Option A. -> ₹ 224
:
A
Area of parallelogram = Base × corresponding height
Area of parallelogram = 8 × (1.75 × 8)
Area of parallelogram= 112m2 .
Total cost of carpeting the hall = Cost per m2×Area
= ₹ 2/m2 × 112 m2 = ₹ 224.
:
A
Area of parallelogram = Base × corresponding height
Area of parallelogram = 8 × (1.75 × 8)
Area of parallelogram= 112m2 .
Total cost of carpeting the hall = Cost per m2×Area
= ₹ 2/m2 × 112 m2 = ₹ 224.