Area And Perimeter(7th Grade > Mathematics ) Questions and answers for exam Preparation

7th Grade > Mathematics

AREA AND PERIMETER MCQs

Perimeter And Area

Total Questions : 99 | Page 1 of 10 pages

Question 1. Which of these is SI unit of area?

Sq. m
Sq. cm
Sq. inch
Sq. ft

Discuss Question

Answer: Option A. -> Sq. m
:
A
The metreis the SI unit and hence, sq. m is in the SI units of area.

Question 2. What is the length of the side of a square of area 64

c m^{2}

16 cm
8 cm
4 cm
32 cm

Discuss Question

Answer: Option B. -> 8 cm
:
B
Area of a square =Side

\times

Side

\Rightarrow

Side

\times

Side = 64

c m^{2}

When we look at the factors of 16,
64 = 64 x 1
64 = 32 x 2
64 = 16 x 4
64 = 8 x 8
Since the sides have to be equal, it has to be 8 cm long as 8

\times

8 = 64

∴

Side will be 8 cm long.

Question 3. Find the area of the given figure if the area of each small square is 1

c m^{2}

5 cm2
10 cm2
15 cm2
20 cm2

Discuss Question

Answer: Option B. -> 10 cm2
:
B
There are 10 small squares in the given figure.
Area of the small square = 1

c m^{2}

\Rightarrow

Area of the given figure
= 10

\times

Area of one square
= 10

\times

c m^{2}

= 10

c m^{2}

Question 4. Which of the following is not a unit of area?

cm2
m2
inch2
dm

Discuss Question

Answer: Option D. -> dm
:
D
Decimeter is not a unit of area. Units of area are given as squared units

Question 5. The length and breadth of a rectangle is 4cm and 5cm respectively. What is its area?

9 cm2
18 cm2
20 cm2
16 cm2

Discuss Question

Answer: Option C. -> 20 cm2
:
C
Area of a rectangle = Length

\times

Breadth
= 4

\times

5
= 20

c m^{2}

Question 6. If the area of a rectangle is 63

c m^{2}

and its breadth is 7 cm, then find its length.

6 cm
7 cm
8 cm
9 cm

Discuss Question

Answer: Option D. -> 9 cm
:
D
Given:
The breadth of a rectangle = 7 cm
Area of the rectangle = 63

c m^{2}

Area of a rectangle = length

\times

breadth
63

c m^{2}

= length

\times

7 cm

length = \frac{A r e a}{b r e a d t h}

= \frac{63 c m^{2}}{7 c m}

= 9 c m

Question 7. Ali runs along the sides of a square park whose side is 10 m long. Find the distance covered by Ali if he ran around the park twice.

40 m
60 m
80 m
100 m

Discuss Question

Answer: Option C. -> 80 m
:
C
Given: Side of the Square = 10 m
Since Ali isrunningaround the park, he runsalong theboundary i.e. the perimeter of the park.
Perimeter of a square = 4

\times

Side
= 4

\times

10 m
= 40 m
Distance covered by Ali in two rounds of the park =2

\times

Perimeter
= 2

\times

40 m
= 80 m

Question 8. Puja has two ropes measuring 5 m and 6 m. She ties a goat at point A with the 5 m rope and ties another goat at point B with the 6 m rope. Find out the ratio of areas grazed at point A and point B. The goats can only move inside the field.

25:36
26:37
24:36
25:37

Discuss Question

Answer: Option A. -> 25:36
:
A
The area grazed by both the goats will be circular in shape as they are moving at a constant distance from a fixed point.
Hence, the area grazed when a goat is tied at a point with a rope would be a circle with radius equal to the length of the rope.
Area of a circle =

π r^{2}

.
Hence, the required ratio =

\frac{A r e a a t A}{A r e a a t B}

(\frac{π r_{A}}{π r_{B}})^{2}

(\frac{r_{A}}{r_{B}})^{2}

(\frac{5}{6})^{2}

= 25:36 .

Question 9. Raj is living in a big room. The dimension of the room is 15.6 m x 19.5 m. He wants to cover the floor with the tiles, each of them measuring 120 cm x 150 cm. Find the exact number of tiles required by Raj to cover the floor.

Discuss Question

Answer: Option A. -> 169
:
A
First of all, we have to convert all the dimensions into the same unit. ( 1 m = 100 cm )
The number of tiles

\times

Area of each tile = Area of the entire room.

\Rightarrow

Number of tiles =

\frac{15.6 \times 19.5}{1.2 \times 1.5}

= 169tiles.

Question 10. A hall is in the shape of a parallelogram. One of the parallel walls measures 8 m. The perpendicular distance corresponding to that wall is 1.75 times the length of this wall. If the cost of carpeting the hall is ₹ 2 per