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Quantitative Aptitude

PERCENTAGE MCQs

Percentages

Total Questions : 2296 | Page 6 of 230 pages
Question 51.

Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get?

  1.    57%
  2.    60%
  3.    65%
  4.    90%
 Discuss Question
Answer: Option A. -> 57%

Total number of votes polled = (1136 + 7636 + 11628) = 20400.


 So, Required percentage =  \(\left(\frac{11628}{20400}\times100\right) \)   %  = 57 %

Question 52.

Two tailors X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?

  1.    Rs. 200
  2.    Rs. 250
  3.    Rs. 300
  4.    None of these
 Discuss Question
Answer: Option B. -> Rs. 250

Let the sum paid to Y per week be Rs. z.


Then, z + 120% of z = 550.


\(z+\frac{120}{100}z = 550.\)


\(\frac{11}{5}z=550.\)


\(z=\left(\frac{550\times5}{11}\right) = 250.\)

Question 53.

Gauri went to the stationers and bought things worth Rs. 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?

  1.    Rs. 15
  2.    Rs. 15.70
  3.    Rs. 19.70
  4.    Rs. 20
 Discuss Question
Answer: Option C. -> Rs. 19.70

Let the amount taxable purchases be Rs. x.


Then, 6% of x  =  \(\frac{30}{100}\)


x = \(\left(\frac{30}{100}\times\frac{100}{6}\right)=5.\)


So, Cost of tax free items = Rs. [25 - (5 + 0.30)] = Rs. 19.70

Question 54.

Rajeev buys good worth Rs. 6650. He gets a rebate of 6% on it. After getting the rebate, he pays sales tax @ 10%. Find the amount he will have to pay for the

  1.    Rs. 6876.10
  2.    Rs. 6999.20
  3.    Rs. 6654
  4.    Rs. 7000
 Discuss Question
Answer: Option A. -> Rs. 6876.10

Rebate = 6% of Rs. 6650 = Rs. \(\left(\frac{6}{100}\times6650\right)=Rs.399.\)


Sales tax = 10% of Rs. (6650 - 399) = Rs. \(\left(\frac{10}{100}\times6251\right)=Rs.625.10.\)


So, Final amount = Rs. (6251 + 625.10) = Rs. 6876.10

Question 55.

The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:

  1.    4.37%
  2.    5%
  3.    6%
  4.    8.75%
 Discuss Question
Answer: Option B. -> 5%

Increase in 10 years = (262500 - 175000) = 87500.


Increase% = \(\left(\frac{87500}{175000}\times100\right)\) %= 50%


So, Required average =  \(\left(\frac{50}{10}\right)\)  % = 5%

Question 56.

Express 56% as a fraction:

  1.    16/25
  2.    14/25
  3.    7/25
  4.    18/25
  5.    None of these
 Discuss Question
Answer: Option B. -> 14/25
 -  56% = 56/100= 14/25
Question 57.

Express 0.6% as a fraction:

  1.    3/500
  2.    6/125
  3.    3/25
  4.    6/100
  5.    None of these
 Discuss Question
Answer: Option A. -> 3/500
 -  0.6 =6/1000 = 3/500
Question 58.

Express 0.008% as a fraction:

  1.    1/2500
  2.    8/125
  3.    1/1250
  4.    8/1250
  5.    None of these
 Discuss Question
Answer: Option C. -> 1/1250
 -  0.008% = 0.008/100 = 1/1250
Question 59.

Express 28 as a Decimal:

  1.    28/100
  2.    7/25
  3.    0.28
  4.    2.8
  5.    None of these
 Discuss Question
Answer: Option C. -> 0.28
 -  28% = 28/100 =0.28
Question 60.

Express 0.2% as a Decimal:

  1.    2
  2.    0.2
  3.    0.02
  4.    0.002
  5.    None of these
 Discuss Question
Answer: Option D. -> 0.002
 -  0.2% =0.2/100 = 0.002

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