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Quantitative Aptitude

PERCENTAGE MCQs

Percentages

Total Questions : 2296 | Page 2 of 230 pages
Question 11.

  1. The tax on a commodity is diminished by 20% and its consumption increases by 15%. The effect on revenue is :

  1.    It is decreases by 8 %
  2.    It is increses by 8 %
  3.    no change in revenue
  4.    none of these
 Discuss Question
Answer: Option A. -> It is decreases by 8 %
Question 12.

  1. The length of a rectangle is increased by 60%. By what per cent would the width have to be decreased to maintain the same area?

  1.    35 %
  2.    37.5 %
  3.    40%
  4.    none of these
 Discuss Question
Answer: Option B. -> 37.5 %
Question 13.
  1. If population increases at 4% p.a. what will be the population of a city 2 years hence if it is 81250 now?

  1.    85788.
  2.    87880
  3.    89780
  4.    none of these
 Discuss Question
Answer: Option B. -> 87880
To solve this question, we can use the formula for compound interest:
A = P(1 + r/n)^(nt)
where A is the final amount, P is the initial amount, r is the annual interest rate, n is the number of times the interest is compounded per year, and t is the time period in years.
In this case, P = 81250, r = 4%, n = 1 (since interest is compounded once per year), and t = 2.
Plugging in these values, we get:
A = 81250(1 + 0.04/1)^(1*2)= 87880
Therefore, the population of the city 2 years hence will be 87880, which is option B.
Some relevant definitions and formulas related to compound interest are:
Compound interest: Interest that is calculated not only on the initial amount (principal), but also on the accumulated interest from previous periods.Annual interest rate: The rate at which interest is charged or paid per year, usually expressed as a percentage.Compounding period: The frequency at which interest is calculated and added to the principal, such as daily, monthly, or annually.Principal: The initial amount of money on which interest is calculated.Final amount: The total amount of money after interest has been added.Formula for compound interest: A = P(1 + r/n)^(nt), where A is the final amount, P is the initial amount, r is the annual interest rate, n is the number of times the interest is compounded per year, and t is the time period in years.If you think the solution is wrong then please provide your own solution below in the comments section .
Question 14.
  1. To 5 litres of 20% sulphuric acid, 5 litres of 100% pure sulphuric acid is added. What is the strength of the acid in the mixture now?

  1.    40%
  2.    50%
  3.    60%
  4.    70%
 Discuss Question
Answer: Option C. -> 60%

The strength of an acid can be measured using the concept of molarity. Molarity is defined as the number of moles of solute present in one litre of the solution.
Lets denote the strength of the 20% sulphuric acid as M1 and the strength of the 100% pure sulphuric acid as M2.
The total volume of the mixture is 10 litres.
The amount of sulphuric acid in the mixture is 5 litres of 20% acid, which is equal to 1 litre of 100% acid.
Therefore, the total amount of acid in the mixture is 6 litres.
The strength of the mixture can be calculated by using the formula:
Mixture Strength = (M1 x Volume of 20% acid + M2 x Volume of 100% acid)/Total Volume
Substituting the values, we get:
Mixture Strength = (20% x 5 litres + 100% x 1 litre)/10 litres
Simplifying, we get:
Mixture Strength = (100 + 10)/10
Therefore, the strength of the acid in the mixture is 60%.
Hence, the correct answer is Option C: 60%.

If you think the solution is wrong then please provide your own solution below in the comments section .

Question 15.
  1. If sugar is 500% costlier than wheat, by what per cent is wheat cheaper than sugar?

  1.    \(83\frac{1}{3}\)
  2.    \(84\frac{1}{3}\)
  3.    \(85\frac{1}{3}\)
  4.    \(86\frac{1}{3}\)
 Discuss Question
Answer: Option A. -> \(83\frac{1}{3}\)
The given problem can be solved by using the concept of percentage increase and decrease. Let us assume the price of wheat to be x, then the price of sugar will be 5x (as sugar is 500% costlier than wheat).
To calculate the percentage difference between the prices of sugar and wheat, we can use the following formula:
Percentage change = [(final value - initial value) / initial value] x 100
Let us apply this formula to find out the percentage decrease in the price of wheat as compared to sugar:
Percentage decrease = [(5x - x) / 5x] x 100= [4x / 5x] x 100= 80%
Hence, the percentage by which wheat is cheaper than sugar is 80%. However, this is not one of the options given in the question. To get the required answer, we need to calculate the percentage of the original value (sugar) that represents the difference between sugar and wheat.
Let us represent this percentage by y:
y% of 5x = 4x
y/100 * 5x = 4x
y = (4x / 5x) * 100
y = 80%
Therefore, the answer is option A, i.e., wheat is 83 1/3 % cheaper than sugar.If you think the solution is wrong then please provide your own solution below in the comments section .
Question 16.

  1. Price of sugar is increased by 30%. Cut in consumption should be ________% (approx.) to give a rise of 10% in expenditure.

  1.    13
  2.    15
  3.    17
  4.    19
 Discuss Question
Answer: Option B. -> 15
Question 17.
  1. 5% people of a village in Sri Lanka died by bombardment, 15% of the remainder left the village on account of fear. If now the population is reduced to 3553, how much was it in the beginning?

  1.    4100
  2.    4200
  3.    4300
  4.    4400
 Discuss Question
Answer: Option D. -> 4400

Let the initial population of the village be x.

Now, 5% of x = (5/100)*x = (x/20) people died due to bombardment.

So, (x - (x/20)) = (95/100)*x = 0.95x people are remaining in the village after the bombardment.

15% of 0.95x = (15/100)*(0.95x) = (0.15x) people left the village due to fear.

So, (0.95x - 0.15x) = (0.8x) people are remaining in the village after the bombardment and fear.

We know, (0.8x) = 3553 (given)

Therefore, 0.8x = 3553

x = (3553/0.8)

x = 4416.25

Hence, the initial population of the village = 4416.25

Rounding off,

Initial population of the village = 4400

Therefore, option D is the correct answer.

Explanation:

Population: Population refers to the total number of people inhabiting a particular place or area at a given time.

Bombardment: Bombardment refers to an action in which a place or an area is attacked with bombs or firearms.

Percentage: Percentage refers to a fraction or ratio expressed as a part of 100. It is denoted by the symbol%.

Formula:
Let the initial population of the village be x

Then, 5% of x = (5/100)*x = (x/20)

15% of 0.95x = (15/100)*(0.95x) = (0.15x)

So, (0.8x) = 3553

Therefore, 0.8x = 3553

x = (3553/0.8)

x = 4416.25

Rounding off,

Initial population of the village = 4400

If you think the solution is wrong then please provide your own solution below in the comments section .

Question 18.

  1. Sharda sold two rings at Rs 39900 each. On one she gained 5% and on the other she lost 5%. What was her total gain or loss per cent?

  1.    loss \(\frac{1}{3}\)
  2.    gain \(\frac{1}{3}\)
  3.    loss\(\frac{1}{4}\)
  4.    gain  \(\frac{1}{4}\)
 Discuss Question
Answer: Option C. -> loss\(\frac{1}{4}\)
Question 19.

  1. Calculation shows that an angle is \(37\frac{1^{0}}{2}\). The size obtained by drawing and measurement is 36°. Find the error per cent?

  1.    3%
  2.    4 %
  3.    5 %
  4.    6 %
 Discuss Question
Answer: Option B. -> 4 %
Question 20.
  1. 20% of which number exceeds a sixth of it by 10?

  1.    100
  2.    200
  3.    300
  4.    400
 Discuss Question
Answer: Option C. -> 300
To solve this question, we must use the given information to form an equation and then solve for the unknown number.

20% of a number: This is equal to 20/100 of the number, which can be written as 0.2x, where x is the number.
A sixth of it: This is equal to 1/6 of the number, which can be written as (1/6)x.
Exceeds by 10: This means that the 20% of the number must be 10 greater than 1/6 of the number.

Using the given information, we can form the following equation:

0.2x = (1/6)x + 10

Solving for x, we get:

x = 300

Therefore, the correct answer is option C. 300.

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