Quantitative Aptitude
PERCENTAGE MCQs
Percentages
Total Questions : 2296
| Page 1 of 230 pages
Answer: Option D. -> \(\frac{1}{250}\)
Answer: Option B. -> Rs.7.50
The given expression is: 5% of [50% of Rs. 300]
Using BODMAS rule, we perform the operation inside the bracket first and then simplify the expression further.
50% of Rs. 300 = (50/100) × 300 = Rs. 150
Now, we need to find 5% of Rs. 150.
To find 5% of a value, we can simply multiply the value by 5/100 or 0.05.
Therefore, 5% of Rs. 150 = (5/100) × 150 = Rs. 7.50
Hence, the correct answer is option B, Rs. 7.50.
Let's understand the concepts and formulas used in this problem in more detail:
The given expression is: 5% of [50% of Rs. 300]
Using BODMAS rule, we perform the operation inside the bracket first and then simplify the expression further.
50% of Rs. 300 = (50/100) × 300 = Rs. 150
Now, we need to find 5% of Rs. 150.
To find 5% of a value, we can simply multiply the value by 5/100 or 0.05.
Therefore, 5% of Rs. 150 = (5/100) × 150 = Rs. 7.50
Hence, the correct answer is option B, Rs. 7.50.
Let's understand the concepts and formulas used in this problem in more detail:
- BODMAS Rule: BODMAS stands for Bracket, Order, Division, Multiplication, Addition, and Subtraction. It is a rule used to simplify mathematical expressions with multiple operations. According to the rule, we must perform the operations in the following order:
- Operations within the bracket
- Exponents or powers
- Division or multiplication (whichever comes first from left to right)
- Addition or subtraction (whichever comes first from left to right)
- Percentage: Percentage is a way of expressing a number as a fraction of 100. We use the symbol "%" to denote percentage. For example, 50% means 50/100 or 0.5.
- Finding a percentage of a value: To find a percentage of a value, we can multiply the value by the percentage in decimal form. For example, to find 10% of 200, we can multiply 200 by 0.1, which gives 20.
Answer: Option C. -> 1500
Answer: Option A. -> \(33\frac{1}{3}\)
Answer: Option C. -> C
Let's assume that B sells his goods at a price of $x$. As per the question, A sells his goods at 50% cheaper than B. Therefore, A's selling price would be 50% less than $x$, which can be calculated as follows:
A's selling price = $x - 50%$ of $x$A's selling price = $x - 0.5x$A's selling price = $0.5x$
Now, let's assume that C sells his goods at a price of $y$. As per the question, A's goods are dearer than C's goods. Therefore, A's selling price would be greater than $y$, which can be expressed as:
A's selling price > $y$
We have already calculated A's selling price as $0.5x$. Therefore, the above equation can be written as:
$0.5x > y$
We can further simplify the above equation as:
x > 2y
This means that B's selling price is more than twice the selling price of C. Hence, C's goods are the cheapest among the three.
To summarize:
Let's assume that B sells his goods at a price of $x$. As per the question, A sells his goods at 50% cheaper than B. Therefore, A's selling price would be 50% less than $x$, which can be calculated as follows:
A's selling price = $x - 50%$ of $x$A's selling price = $x - 0.5x$A's selling price = $0.5x$
Now, let's assume that C sells his goods at a price of $y$. As per the question, A's goods are dearer than C's goods. Therefore, A's selling price would be greater than $y$, which can be expressed as:
A's selling price > $y$
We have already calculated A's selling price as $0.5x$. Therefore, the above equation can be written as:
$0.5x > y$
We can further simplify the above equation as:
x > 2y
This means that B's selling price is more than twice the selling price of C. Hence, C's goods are the cheapest among the three.
To summarize:
- B sells his goods at a price of $x$.
- A sells his goods at a price of $0.5x$.
- C sells his goods at a price of $y$.
- A's goods are dearer than C's goods, i.e., $0.5x > y$.
- B's selling price is more than twice the selling price of C, i.e., $x > 2y$.
- Therefore, C's goods are the cheapest among the three.
Answer: Option C. -> \(83\frac{1}{3}\)
Answer: Option C. -> 1500