7th Grade > Physics
MOTION AND TIME MCQs
Total Questions : 115
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Answer: Option D. -> 4 h
:
D
Given:
Distance travelled in 2h=50km.
Speed = DistanceTime .
⇒Speed=502 = 25 kmh−1
Now, to travel 100km at the same speed as given above,
Speed =25kmh−1=DistanceTime
⇒Time =100km25kmh−1
⇒ Time =10025=4h.
:
D
Given:
Distance travelled in 2h=50km.
Speed = DistanceTime .
⇒Speed=502 = 25 kmh−1
Now, to travel 100km at the same speed as given above,
Speed =25kmh−1=DistanceTime
⇒Time =100km25kmh−1
⇒ Time =10025=4h.
Answer: Option A. -> The body is at rest.
:
A
In a position-time graph, the X-axis indicates time and the Y-axis indicates the position.
If the graph is a straight line parallel to the X-axis, it means that the position of the body is the same at different intervals of time.
This can happen only when the body is at rest.
:
A
In a position-time graph, the X-axis indicates time and the Y-axis indicates the position.
If the graph is a straight line parallel to the X-axis, it means that the position of the body is the same at different intervals of time.
This can happen only when the body is at rest.
Question 4. A boy is driving a car at a speed of 60 km/hr from his home to college. In the return journey, his speed was half of what it was in the ongoing journey. Calculate the total time of the entire journey. Given: Distance between college and home is 12 km. Also, find the average speed of the car for the entire journey. [5 MARKS]
:
Distance: 2 Marks
Average Speed: 1 Mark
Formula: 1 Mark
Steps: 1 Mark
From home to school:
Speed of car = 60 km/hr
Distance = 12 km
Time taken =distancespeed=1260=0.2hrs
From school to home:
Speed of car =602= 30 km/hr
Distance = 12 km
Time taken =1230=25=0.4hrs
Total time taken by car = 0.2 + 0.4 = 0.6 hrs
Average Speed =TotalDistancetravelledTotalTime
=240.6
= 40 km/hr
Answer: Option A. -> 20 km h−1
:
A
Given:
Odometer reading, before the trip =22256km.
Odometer reading, after the trip =22356km.
So the distance travelled in the trip=22356−22256=100km.
Time taken for the trip =5h.
Average speed = Total distance travelledTotal time taken
∴Average speed =1005=20kmh−1.
:
A
Given:
Odometer reading, before the trip =22256km.
Odometer reading, after the trip =22356km.
So the distance travelled in the trip=22356−22256=100km.
Time taken for the trip =5h.
Average speed = Total distance travelledTotal time taken
∴Average speed =1005=20kmh−1.
Answer: Option B. -> False
:
B
The S.I unit of distance is metre, not kilometre.
:
B
The S.I unit of distance is metre, not kilometre.
Answer: Option B. -> 72
:
B
Given that the speed of a car =20ms−1=20m1s
[1m=11000km,1s=13600h]
=20×11000km1×160×60h
=20×36001000kmh−1
=72kmh−1.
:
B
Given that the speed of a car =20ms−1=20m1s
[1m=11000km,1s=13600h]
=20×11000km1×160×60h
=20×36001000kmh−1
=72kmh−1.
Answer: Option A. -> non-uniform
:
A
When a body is moving in a straight line and its speed changes frequently, it implies that the bodywill cover unequal distances in equal intervals of time. Hence this is a non-uniform motion.
:
A
When a body is moving in a straight line and its speed changes frequently, it implies that the bodywill cover unequal distances in equal intervals of time. Hence this is a non-uniform motion.
Answer: Option A. -> 30 m
:
A
Given:
Speed = 15 ms−1
Time = 2 s
Distance = Speed × Time
= 15 × 2 = 30m.
:
A
Given:
Speed = 15 ms−1
Time = 2 s
Distance = Speed × Time
= 15 × 2 = 30m.