12th Grade > Chemistry
HYDROCARBONS MCQs
Total Questions : 28
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Answer: Option C. -> I > IV > II > III
:
C
Ethane = 1.54 A0, Ethene = 1.33 A0, Ethyne = 1.21 A0, Benzene = 1.39 A0
:
C
Ethane = 1.54 A0, Ethene = 1.33 A0, Ethyne = 1.21 A0, Benzene = 1.39 A0
Answer: Option A. -> The members of the series are isomers of each other
:
A
The difference between any two successive members of the homologous series -CH2-i.e., the molecular weight of every two adjacent members differ by 14.
(CH2=12+2=14)
:
A
The difference between any two successive members of the homologous series -CH2-i.e., the molecular weight of every two adjacent members differ by 14.
(CH2=12+2=14)
Answer: Option B. -> 4
:
B
Ratio=σbondsπbonds=123=4
:
B
Ratio=σbondsπbonds=123=4
Answer: Option B. -> Ag2C2
:
B
HC≡CH+2AgNO3NH4OH−−−−−→Ag−C≡C−Ag+2NH4NO3+2H2O
:
B
HC≡CH+2AgNO3NH4OH−−−−−→Ag−C≡C−Ag+2NH4NO3+2H2O
Answer: Option D. -> 'Y' gives 2,3 - dimethyl butene on wurtz reaction
:
D
X is CH3−CHBr−CH3 - Markovnikov product.
On the other hand,Y is obtained via peroxide or anti-Markovnikov addition: Y is CH3−CH2−CH2−Br
'Y' gives n-hexane on Wurtz reaction
:
D
X is CH3−CHBr−CH3 - Markovnikov product.
On the other hand,Y is obtained via peroxide or anti-Markovnikov addition: Y is CH3−CH2−CH2−Br
'Y' gives n-hexane on Wurtz reaction
Answer: Option A. -> C6H6+C2H5ClAlCl3−−−→C6H5C2H5+HCl
:
A
C6H6+C2H5ClAlCl3−−−→C6H5−C2H5+HCl
:
A
C6H6+C2H5ClAlCl3−−−→C6H5−C2H5+HCl
Answer: Option B. -> Basic and > 7
:
B
during electrolysis NaOH(Strong base) is formed.
:
B
during electrolysis NaOH(Strong base) is formed.