Answer: Option C. -> Monday

Answer: Option C. -> Monday

Answer: Option B. -> 2014

Answer: Option A. -> Thursday

Answer: Option C. -> Tuesday

Answer: Option C. -> Thursday
Answer: (c)
4th Saturday = 22nd day
3rd Saturday = 22 - 7 = 15th day
∴ 13th day - Saturday - 2 = Thursday

Answer: Option C. -> Tuesday
Answer: (c)
Here, 27th March 1995 was Monday.
Now, for calculating the total number of odd days. first, we calculate the total number of days till 1 November 1994.
∴  Number of days in March, 1995 = 27
Number of days in February 1995 = 28
Number of days in January 1995 = 31
Number of days in December 1994 = 31
Number of days in November 1994 = 29
Total number of days = 146
∴ Number of odd days = $146/7$ = 20$6/7$
So, 6 odd days
∴ On November 1, 1994 = Monday - 6
= Tuesday

Answer: Option B. -> Tuesday
Answer: (b)
Tomorrow = Friday
3 days after tomorrow = 15th June = Friday + 3 odd days = Monday
Days from 15th to 30th June = 15
15 ÷ 7 = 7)15(2 =>remainder 1 odd day
30th June = Monday + 1 odd day = Tuesday

Answer: Option D. -> Sunday
Answer: (d)
Since Total days from 15th August, 2011 to 17 September, 2011 = 33
33 ÷ 7 => 7)33(4 = remainder 5 odd days
∴ Required day = Tuesday + 5 odd days
= Sunday

Answer: Option B. -> Monday
Answer: (b)
1st April 1901 means 1900 complete years + first 3 months of 1901 + 1 day of April
Number of odd days in 1600 yrs = 0
Number of odd days in 300 yrs = 1
Number of odd days in 1901 yrs
January
3
February
0
March
3
April
1
= 3 + 0 + 3 + 1 = 7
⇒ 0 odd days
Total number of odd days till 1st April 1901 = 0 + 1 + 0 = 1
So, the required day was Monday.