Quantitative Aptitude
CHAIN RULE MCQs
Cost of x metres = Rs. d.
Cost of 1 metre = Rs. \(\left(\frac{d}{x}\right)\)
Cost of y metres = Rs. \(\left(\frac{d}{x}.y\right)\) = Rs. \(\left(\frac{yd}{x}\right)\)
After 10 days : 150 men had food for 35 days.
Suppose 125 men had food for x days.
Now, Less men, More days (Indirect Proportion)
So, 125 : 150 :: 35 : x \(\Leftrightarrow\) 125 x x = 150 x 35
x = \(\frac{150\times35}{125}\)
x = 42.
Work done = \(\frac{5}{8}\)
Balance work = \(\left(1-\frac{5}{8}\right)=\frac{3}{8}\)
Let the required number of days be x.
Then, \( \frac{5}{8}:\frac{3}{8}=::10:x \Leftrightarrow \frac{5}{8}\times x =\frac{3}{8}\times10\)
x = \(\left(\frac{3}{8}\times10\times\frac{5}{8}\right) \)
x= 6.
Let the required weight be x kg.
Less weight, Less cost (Direct Proportion)
So, 250 : 200 :: 60 : x \(\Leftrightarrow \) 250 x x = (200 x 60)
x = \(\frac{(200\times60)}{250}\)
x = 48.
Let the required number of revolutions made by larger wheel be x.
Then, More cogs, Less revolutions (Indirect Proportion)
So, 14 : 6 :: 21 : x \( \Leftrightarrow\) 14 x x = 6 x 21
x = \(\frac{6\times21}{14}\)
x = 9.