Answer: Option C. -> Sunday
Answer: (c)
Odd days in 1600 yrs = 0
Odd days in 400 yrs = 0 5 yrs = (4 ordinary year + 1 leap year)
= (4 x 1+ 1 x 2) = 6 odd days
Month
Odd days
January
3
February
0
(ordinary year) 
March
3
April
2
May
0 i.e,(28 ÷ 7)
Total
8
Total odd days = 8 + 6 = 14 = 0 odd day
∴ Required day Sunday

Answer: Option D. -> Tuesday
Answer: (d)
1st January 1901 means
= (1900 yrs and 1 day)
Now, 1600 yrs have 0 odd days,
300 yrs have 1 odd day and 1 day has 1 odd day.
Total number of odd days = 0 + 1 + 1 = 2 days
∴ the day on 1st January, 1901 was Tuesday.

Answer: Option B. -> Friday
Answer: (b)
28th August 2009 means,
2008 complete years + First 7 months of the year 2009 + 28 days of August
Number of odd days in 2000 yrs = 0
Number of odd days from 2001 yrs to 2008 yrs
 
Year
Number of odd days
2001
1
2002
1
2003
1
2004
2
2005
1
2006
1
2007
1
2008
2
 
2001 2002 2003 2004 2005 2006 2007 2008  1 1 1 2 1 1 1 2
=1+1+1+ 2+ 1+1+1+2 = 10
= 7 x1+ 3 = 3 odd days
Number of odd days in 2009,
Month
Odd days
January
3
February
0
(ordinary year) 
March
3
April
2
May
3
June
2
July
3
August
0
January February March April May July  August 3 0 3 2 3 2 3 0
= 3 + 0 + 3 + 2 + 3 + 2 + 3 + 0
= 16 = 7 x 2 + 2 = 2 odd days
Total number of odd days till 28th August 2009
= 0 + 3 + 2 = 5
So, the required day is Friday.

Answer: Option A. -> Saturday
Answer: (a)
A day before yesterday = Tuesday
Yesterday = Tuesday + 1 = Wednesday
Today = Wednesday + 1 = Thursday
Tomorrow = Thursday + 1= Friday
∴ Day after tomorrow = Friday + 1 = Saturday

Answer: Option C. -> Day after tomorrow
Answer: (c)
If the day before yesterday was Wednesday, then today will be Friday and the day after tomorrow will be Sunday.

Answer: Option D. -> Thursday
Answer: (d)
26th January 2011 to 26th January 2012 will be considered as an ordinary year because 26th January in 2012 (a leap year) comes before 29th February.
Hence, the period of this one year will have only 1 odd day.
Since 26th January 2011 = Wednesday
∴ 26th January 2012 = Wednesday + 1 odd day
= Thursday

Answer: Option C. -> 26th
Answer: (c)
According to the question,
National day = 4th Saturday
Since, 1st day = Tuesday
∴ 1st Saturday = Tuesday + 4 = 1 + 4 = 5th day
∴ 2nd Saturday = 5 + 7 = 12th day
3rd Saturday = 12 + 7 = 19th day
4th Saturday = 19 + 7 = 26th day
So, National day was celebrated on 26th of that month.

Answer: Option B. -> Friday
Answer: (b)
As we know that, first and last day of an ordinary year is the same.
Since, 1st day = Friday
⇒ Last day = Friday

Answer: Option B. -> Tuesday
Answer: (b)
Number of days in 1996 (366-26) = 340
Number of days in 1997 = 365
Number of days in 1998 = 365
Number of days in 1999 = 365 
Number of days from January 2000 to July 2000 = 31 + 29 + 31 + 30 + 31 + 30 + 31
= 213 
Number of days from 1st to 15th August, 2000 = 15
∴ Total days = 340 + 365 + 365 + 365 + 213 + 15 = 1663
∴ 1663 ÷ 7 = remainder 4
∴ 1663 days = (237 X 7 + 4) days = 237 weeks + 4 days
∴  Number of odd days = 4
∴  Day on 15th August, 2000 = Friday + 4 Odd days = Tuesday

Answer: Option B. -> Saturday
Answer: (b)
Since, December 17, 1899 - Saturday
December 17, 1900 - Sunday
December 18, 1901 - Tuesday
∴ December 22, 1901 - Saturday