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Total Questions : 1601 | Page 2 of 161 pages
Question 11. The 19 cm × 9 cm side of a brick as seen in the wall face, is generally known as
  1.     Stretcher
  2.     Face
  3.     Front
  4.     Header
 Discuss Question
Answer: Option A. ->  Stretcher
Explanation :
Question 12. The 19 cm × 9 cm side of a brick as seen in the wall face, is generally known as
  1.     Stretcher
  2.     Face
  3.     Front
  4.     Header
 Discuss Question
Answer: Option A. ->  Stretcher
Explanation :
Question 13. The 19 cm × 9 cm side of a brick as seen in the wall face, is generally known as
  1.     Stretcher
  2.     Face
  3.     Front
  4.     Header
 Discuss Question
Answer: Option A. ->  Stretcher
Explanation :
Question 14. If (φ) is the angle of repose of soil of weight w kg/m3, the horizontal pressure p at a depth of h meters per metre length of wall, is
  1.     wh × [(1 - sin φ)/(1 + sin φ)]
  2.     (wh/2) × [(1 - sin φ)/(1 + sin φ)]
  3.     wh × √[(1 - sin φ)/(1 + sin φ)]
  4.     wh × √[(1 + sin φ)/(1 - sin φ)]
 Discuss Question
Answer: Option A. ->  wh × [(1 - sin φ)/(1 + sin φ)]
Question 15. If (φ) is the angle of repose of soil of weight w kg/m3, the horizontal pressure p at a depth of h meters per metre length of wall, is
  1.     wh × [(1 - sin φ)/(1 + sin φ)]
  2.     (wh/2) × [(1 - sin φ)/(1 + sin φ)]
  3.     wh × √[(1 - sin φ)/(1 + sin φ)]
  4.     wh × √[(1 + sin φ)/(1 - sin φ)]
 Discuss Question
Answer: Option A. ->  wh × [(1 - sin φ)/(1 + sin φ)]
Question 16. If (φ) is the angle of repose of soil of weight w kg/m3, the horizontal pressure p at a depth of h meters per metre length of wall, is
  1.     wh × [(1 - sin φ)/(1 + sin φ)]
  2.     (wh/2) × [(1 - sin φ)/(1 + sin φ)]
  3.     wh × √[(1 - sin φ)/(1 + sin φ)]
  4.     wh × √[(1 + sin φ)/(1 - sin φ)]
 Discuss Question
Answer: Option A. ->  wh × [(1 - sin φ)/(1 + sin φ)]
Question 17. If (φ) is the angle of repose of soil of weight w kg/m3, the horizontal pressure p at a depth of h meters per metre length of wall, is
  1.     wh × [(1 - sin φ)/(1 + sin φ)]
  2.     (wh/2) × [(1 - sin φ)/(1 + sin φ)]
  3.     wh × √[(1 - sin φ)/(1 + sin φ)]
  4.     wh × √[(1 + sin φ)/(1 - sin φ)]
 Discuss Question
Answer: Option A. ->  wh × [(1 - sin φ)/(1 + sin φ)]
Question 18. The skirting/dado in a bath roof should be upto
  1.     Ceiling
  2.     15 cm above floor level
  3.     200 cm
  4.     Level of the tap
 Discuss Question
Answer: Option C. ->  200 cm
Question 19. The skirting/dado in a bath roof should be upto
  1.     Ceiling
  2.     15 cm above floor level
  3.     200 cm
  4.     Level of the tap
 Discuss Question
Answer: Option C. ->  200 cm
Question 20. The skirting/dado in a bath roof should be upto
  1.     Ceiling
  2.     15 cm above floor level
  3.     200 cm
  4.     Level of the tap
 Discuss Question
Answer: Option C. ->  200 cm

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