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AVERAGES MCQs

Averages

Total Questions : 3752 | Page 6 of 376 pages
Question 51.

The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is:

  1.    17 kg
  2.    20 kg
  3.    26 kg
  4.    31 kg
 Discuss Question
Answer: Option D. -> 31 kg

Let A, B, C represent their respective weights. Then, we have:


A + B + C = (45 x 3) = 135 .... (i)


A + B = (40 x 2) = 80 .... (ii)


B + C = (43 x 2) = 86 ....(iii)


Adding (ii) and (iii), we get: A + 2B + C = 166 .... (iv)


Subtracting (i) from (iv), we get : B = 31.


Threrfore B's weight = 31 kg.

Question 52.

The average weight of 16 boys in a class is 50.25 kg and that of the remaining 8 boys is 45.15 kg. Find the average weights of all the boys in the class.

  1.    47.55 kg
  2.    48 kg
  3.    48.55 kg
  4.    49.25 kg
 Discuss Question
Answer: Option C. -> 48.55 kg

Required average = \(\left(\frac{50.25\times16+45.15\times8}{16+8}\right)\) 


\(=\left(\frac{804+361.20}{24}\right)\)


\(=\frac{1165.20}{24}\)


= 48.55


 

Question 53.

A library has an average of 510 visitors on Sundays and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is:

  1.    250
  2.    276
  3.    280
  4.    285
 Discuss Question
Answer: Option D. -> 285

Since the month begins with a Sunday, to there will be five Sundays in the month.


Required avarage = \(\left(\frac{510\times5+240\times25}{30}\right)\)


= \(\frac{8550}{30}\)


= 285

Question 54.

If the average marks of three batches of 55, 60 and 45 students respectively is 50, 55, 60, then the average marks of all the students is:

  1.    53.33
  2.    54.68
  3.    55
  4.    None of these
 Discuss Question
Answer: Option B. -> 54.68

Required average = \(\left(\frac{55\times50+60\times55+45\times60}{55+60+45}\right)
\)


= \(\left(\frac{2750+3300+2700}{160}\right)\)


= \(\frac{8750}{160}\)


= 54.68

Question 55.

A pupils marks were wrongly entered as 83 instead of 63. Due to that the average marks for the class got increased by half (1/2). The number of pupils in the class is:

  1.    10
  2.    20
  3.    40
  4.    73
 Discuss Question
Answer: Option C. -> 40

Let there be x pupils in the class.


Total increase in marks = \(\left(x\times\frac{1}{2}\right)= \frac{1}{2}\)


Therefore  \(\frac{x}{2}= \left(83-63\right) \Rightarrow \frac{x}{2}= 20 \Rightarrow x = 40.\)

Question 56.

Find the average of all the prime number between 30 and 50?

  1.    38
  2.    38.8
  3.    39
  4.    39.8
  5.    None of these
 Discuss Question
Answer: Option D. -> 39.8
 -  There are 5 prime numbers- 31, 37, 41, 43, 47
 
Average = 31+37+41+43+47 = 199 = 39.8 5 5
Question 57.

The average age of 30 boys of a class is equal to 14 years. When the age of the class teacher is included the average becomes 15 years. Find the age of the class teacher?

  1.    40
  2.    43
  3.    45
  4.    47
  5.    None of these
 Discuss Question
Answer: Option C. -> 45

 -  Total ages of 30 boys = 14 x 30 = 420 years
 
Total age when class teacher is included = 15 x 31 = 465 years
 
Age of class teacher = 465 – 420 = 45 years

Let the age of the class teacher be x years.

We are given that the average age of 30 boys in the class is 14 years. Therefore, the total age of the 30 boys is:

30 * 14 = 420

We are also given that when the age of the class teacher is included, the average age becomes 15 years. Therefore, the total age of the 30 boys and the teacher is:

(30 * 14) + x

The total number of people in the class is 30 boys + 1 teacher = 31.

We can use the formula for the average:

average = total sum / number of elements

We can set up the equation using the two given averages:

15 = (420 + x) / 31

Multiplying both sides by 31, we get:

465 = 420 + x

Subtracting 420 from both sides, we get:

x = 45

Therefore, the age of the class teacher is 45 years.

To summarize the solution:

Let the age of the class teacher be x years.

The total age of the 30 boys is 30 * 14 = 420.

The total age of the 30 boys and the teacher is (30 * 14) + x.

The total number of people in the class is 30 boys + 1 teacher = 31.

Using the formula for the average, we can set up the equation 15 = (420 + x) / 31.

Solving for x, we get x = 45.

Therefore, the age of the class teacher is 45 years.

Question 58.

The Average of marks obtained by 120 candidates in a certain examination is 35. If the average marks of passed candidates is 39 and that of failed candidates is 15, what is the number of candidates who passed the examination?

  1.    95
  2.    100
  3.    105
  4.    110
  5.    None of these
 Discuss Question
Answer: Option B. -> 100
 -  Let the number of passed candidates be a
 
Then total marks =>120 x 35 = 39 a + (120 – a) x 15
 
4200 = 39 a + 1800 – 15 a
 
      a = 100
Question 59.

The average of 11 results is 50. If the average of first 6 results is 49 and that of last 6is 52, find the sixth result?

  1.    50
  2.    56
  3.    60
  4.    64
  5.    None of these
 Discuss Question
Answer: Option B. -> 56
 -  The total of 11 results = 11 x 50 = 550
 
The total of first 6 results = 6 x 49 = 294
 
The total of last 6 results = 6 x 52 = 312
 
The sixth result is common to both:
 
 Sixth result = 294 + 312 – 550 = 56
Question 60.

The average age of a family of 6 members is 22 years. If the age of the  youngest member be 7 years, then what was the average age of the family at the birth of the youngest member?

  1.    16
  2.    18
  3.    20
  4.    22
  5.    None of these
 Discuss Question
Answer: Option B. -> 18
 -  Total age of all members = 6 x 22 = 132 years
7 years ago, total sum of ages = 132 – (6 x 7) = 90 years 
But at that time there were 5 members in the family
 
Average at that time = 90 /5 = 18 years

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