Quantitative Aptitude
AVERAGES MCQs
Averages
Let A, B, C represent their respective weights. Then, we have:
A + B + C = (45 x 3) = 135 .... (i)
A + B = (40 x 2) = 80 .... (ii)
B + C = (43 x 2) = 86 ....(iii)
Adding (ii) and (iii), we get: A + 2B + C = 166 .... (iv)
Subtracting (i) from (iv), we get : B = 31.
Threrfore B's weight = 31 kg.
Required average = \(\left(\frac{50.25\times16+45.15\times8}{16+8}\right)\)
\(=\left(\frac{804+361.20}{24}\right)\)
\(=\frac{1165.20}{24}\)
= 48.55
Since the month begins with a Sunday, to there will be five Sundays in the month.
Required avarage = \(\left(\frac{510\times5+240\times25}{30}\right)\)
= \(\frac{8550}{30}\)
= 285
Required average = \(\left(\frac{55\times50+60\times55+45\times60}{55+60+45}\right)
\)
= \(\left(\frac{2750+3300+2700}{160}\right)\)
= \(\frac{8750}{160}\)
= 54.68
Let there be x pupils in the class.
Total increase in marks = \(\left(x\times\frac{1}{2}\right)= \frac{1}{2}\)
Therefore \(\frac{x}{2}= \left(83-63\right) \Rightarrow \frac{x}{2}= 20 \Rightarrow x = 40.\)
 - There are 5 prime numbers- 31, 37, 41, 43, 47
Average = 31+37+41+43+47 = 199 = 39.8 5 5
- Total ages of 30 boys = 14 x 30 = 420 years
Total age when class teacher is included = 15 x 31 = 465 years
Age of class teacher = 465 – 420 = 45 years
Let the age of the class teacher be x years.
We are given that the average age of 30 boys in the class is 14 years. Therefore, the total age of the 30 boys is:
30 * 14 = 420
We are also given that when the age of the class teacher is included, the average age becomes 15 years. Therefore, the total age of the 30 boys and the teacher is:
(30 * 14) + x
The total number of people in the class is 30 boys + 1 teacher = 31.
We can use the formula for the average:
average = total sum / number of elements
We can set up the equation using the two given averages:
15 = (420 + x) / 31
Multiplying both sides by 31, we get:
465 = 420 + x
Subtracting 420 from both sides, we get:
x = 45
Therefore, the age of the class teacher is 45 years.
To summarize the solution:
Let the age of the class teacher be x years.
The total age of the 30 boys is 30 * 14 = 420.
The total age of the 30 boys and the teacher is (30 * 14) + x.
The total number of people in the class is 30 boys + 1 teacher = 31.
Using the formula for the average, we can set up the equation 15 = (420 + x) / 31.
Solving for x, we get x = 45.
Therefore, the age of the class teacher is 45 years.
 - Let the number of passed candidates be a
Then total marks =>120 x 35 = 39 a + (120 – a) x 15
4200 = 39 a + 1800 – 15 a
a = 100
 - The total of 11 results = 11 x 50 = 550
The total of first 6 results = 6 x 49 = 294
The total of last 6 results = 6 x 52 = 312
The sixth result is common to both:
Sixth result = 294 + 312 – 550 = 56
 - Total age of all members = 6 x 22 = 132 years
7 years ago, total sum of ages = 132 – (6 x 7) = 90 years
But at that time there were 5 members in the family
Average at that time = 90 /5 = 18 years