Quantitative Aptitude
AVERAGES MCQs
Averages
Required run rate = \(\left(\frac{282-(3.2\times10)}{40}\right)=\frac{250}{40}=6.25\)
Required average = \(\left(\frac{67\times2+35\times2+6\times2}{2+2+3}\right)\)
=\(\left(\frac{134+70+18}{7}\right)\)
=\(\frac{222}{7}\)
=\(31\frac{5}{7}years.\)
Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Therefore Required sale = Rs. [ (6500 x 6) - 34009 ]
= Rs. (39000 - 34009)
= Rs. 4991.
Average of 20 numbers = 0.
Sum of 20 numbers (0 x 20) = 0.
It is quite possible that 19 of these numbers may be positive and if their sum is a then 20th number is (-a).
Total weight increased = (8 x 2.5) kg = 20 kg.
Weight of new person = (65 + 20) kg = 85 kg.
Let the average age of the whole team by x years.
11x - (26 + 29) = 9(x -1)
11x - 9x = 46
2x = 46
x = 23.
So, average age of the team is 23 years.
Let P, Q and R represent their respective monthly incomes. Then, we have:
P + Q = (5050 x 2) = 10100 .... (i)
Q + R = (6250 x 2) = 12500 .... (ii)
P + R = (5200 x 2) = 10400 .... (iii)
Adding (i), (ii) and (iii), we get: 2(P + Q + R) = 33000 or P + Q + R = 16500 .... (iv)
Subtracting (ii) from (iv), we get P = 4000.
Therefore P's monthly income = Rs. 4000.
Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.
Therefore Husband's present age = (90 - 50) years = 40 years.
Total quantity of petrol
consumed in 3 years = \(\left(\frac{4000}{7.50}+\frac{4000}{8}+\frac{4000}{8.50}\right)liters\)
\(=4000\left(\frac{2}{15}+\frac{1}{8}+\frac{2}{17}\right)liters\)
\(=\left(\frac{76700}{51}\right)liters\)
Total amount spent = Rs. (3 x 4000) = Rs. 12000.
Therefore Average Cost = Rs.\(\left(\frac{1700\times51}{76700}\right)=Rs.\frac{6120}{767}=Rs.7.98\)
In Aruns opinion, his weight is greater than 65 kg but less than 72 kg. His brother doest not agree with Arun and he thinks that Aruns weight is greater than 60 kg but less than 70 kg. His mothers view is that his weight cannot be greater than 68 kg. If all are them are correct in their estimation, what is the average of different probable weights of Arun?
Let Arun's weight by X kg.
According to Arun, 65 < X < 72
According to Arun's brother, 60 < X < 70.
According to Arun's mother, X <= 68
The values satisfying all the above conditions are 66, 67 and 68.
Therefore Required average = \(\left(\frac{66+67+68}{3}\right)=\left(\frac{201}{3}\right)=67kg.\)