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A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:

Options:
A .  35
B .  \(36\frac{2}{3}\)
C .  \(37\frac{1}{2}\)
D .  40
Answer: Option D

Let distance = x km and usual rate = y kmph.


Then, \(\frac{x}{y}-\frac{x}{y+3}=\frac{40}{60} \Rightarrow2y\left(y+3\right)=9x .......(i) \)


And, \(\frac{x}{y-2}-\frac{x}{y}=\frac{40}{60} \Rightarrow y\left(y-2\right)=3x .......(ii)\)


On dividing (i) by (ii), we get: x = 40.


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