Question
A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:
Answer: Option D
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Let distance = x km and usual rate = y kmph.
Then, \(\frac{x}{y}-\frac{x}{y+3}=\frac{40}{60} \Rightarrow2y\left(y+3\right)=9x .......(i) \)
And, \(\frac{x}{y-2}-\frac{x}{y}=\frac{40}{60} \Rightarrow y\left(y-2\right)=3x .......(ii)\)
On dividing (i) by (ii), we get: x = 40.
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