-  In the series 62 is the 41st term

The given series is an arithmetic progression (A.P.) with the first term 'a' = 2 and the common difference 'd' = 3.5 - 2 = 1.5.

To find the number of terms in the series, we need to determine the last term. We can use the formula for the nth term of an arithmetic progression to find the last term.

The formula for the nth term of an arithmetic progression is given by:

an = a + (n - 1) * d

where an is the nth term of the A.P., a is the first term, d is the common difference, and n is the number of terms.

We need to find the value of n for which the nth term is 62. So, we can write:

62 = 2 + (n - 1) * 1.5

59 = (n - 1) * 1.5

n - 1 = 59 / 1.5

n - 1 = 39.33

n ≈ 40.33

We got a non-integer value of n, which indicates that there are only 40 terms in the series up to 61. The 41st term would exceed 62.

Hence, the correct option is A (41).

To summarize, we used the following concepts/formulas:

• Arithmetic Progression: A sequence of numbers in which the difference between any two consecutive terms is constant.
• Formula for the nth term of an arithmetic progression: an = a + (n - 1) * d
• Calculation of the number of terms in an arithmetic progression using the nth term and the first term.

If you think the solution is wrong then please provide your own solution below in the comments section .