-  The 35th term is 59

To find the 35th term of an arithmetic sequence, we need to use the formula:

an = a1 + (n-1)d

where:

an = the nth term of the sequence

a1 = the first term of the sequence

d = the common difference between consecutive terms

n = the number of the term we want to find

In this case, we are given that the first term, a1, is 8 and the common difference, d, is 1.5. We want to find the 35th term, so we substitute these values into the formula and solve for an:

a35 = 8 + (35-1)1.5

a35 = 8 + 51

a35 = 59

Therefore, the 35th term of the arithmetic sequence with first term 8 and common difference 1.5 is 59.

To summarize, the solution is as follows:

We are given a first term of 8 and a common difference of 1.5.

We use the formula an = a1 + (n-1)d to find the 35th term.

Substituting the given values, we get a35 = 8 + (35-1)1.5.

Simplifying, we get a35 = 8 + 51 = 59.

Therefore, the answer is option D, 59.