Question
If a = 0.1039 , then the velue of \( \sqrt{4a^{2}-4a+1}+3a. is :\)
Answer: Option C
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\( \sqrt{4a^{2}-4a+1}+3a = \sqrt{(a^{2})+(2a)^{2}-2\times1\times2a}+3a\)
= \( \sqrt{(1-2a)^{2}}+3a\)
= (1 - 2a) + 3a
= (1 + a)
= (1 + 0.1039)
= 1.1039
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