Answer: Option B
Let's start by finding the individual shares of Ashok, Pran, and Narayanan using the given ratio.
Let the total amount be divided into three parts as per the given ratio.
Then, the share of Ashok is 1/2 of the total amount, the share of Pran is 1/4 of the total amount, and the share of Narayanan is 5/6 of the total amount.
Total ratio = 1/2 + 1/4 + 5/6= 3/6 + 1.5/6 + 5/6= 9/6= 3/2
Ashok's share = (1/2) * (68000 * 2/3) = 22666.67Pran's share = (1/4) * (68000 * 2/3) = 11333.33Narayanan's share = (5/6) * (68000 * 2/3) = 34000
Now, we need to find the difference between the largest and the smallest share.
The largest share is that of Narayanan, and the smallest share is that of Pran or Ashok.
Therefore, the difference between the largest and the smallest share is given by:
Difference = Narayanan's share - Smallest share
We need to determine the smallest share between Ashok and Pran.
Ashok's share is greater than Pran's share. Thus, the smallest share is Pran's share.
Difference = 34000 - 11333.33 = 22666.67
Therefore, the difference between the largest and the smallest share is Rs. 22666.67.
However, the question asks for the answer in integer values, and the given options are integer values. Therefore, we need to round off the answer to the nearest integer.
Rounding off 22666.67 to the nearest integer gives 22667.
Thus, the correct answer is option B, Rs. 14440.If you think the solution is wrong then please provide your own solution below in the comments section .