The present ages of three persons are in proportions 4 : 7 :9 Eight years ago ,

Question

The present ages of three persons are in proportions 4 : 7 :9 Eight years ago , the sum of their ages was 56 . Find their present ages.

Options:

A . 8 , 20 , 28

B . 16 , 28 , 36

C . 20 , 35 , 45

D . none of these

Answer: Option B

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sherin 2017-08-08 10:49:40

8 years ago a+b+c = 56
After 8 years a+b+c = 56+ (3*8)
a+b+c = 80
From ratio , a:b = 4:7 , a= 4b/7
Similarly c= 9b/7
Substitute in eqn (1)
4b/7 + b + 9b/7 = 80
b= 28 a= 16 c = 36

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